Question

我有两张桌子

订单
- ID
- 日期
- 供应商

项
- ID
- 订单ID
- 价格
- 数量

我正在尝试显示订单中所有商品的总数。像这样......

101 - 12/02/2017 - Sams - $ 327
105 - 12/05/2017 - Sams - $ 544

相反，我的结果显示如下..

101 - 12/02/2017 - Sams - $ 300
101 - 12/02/2017 - Sams - $ 27
105 - 12/05/2017 - Sams - $ 200
105 - 12/05/2017 - Sams - $ 344

所以它给了我订单中每件商品的总数，但不是订单中所有商品的总数，这是我所追求的。这是我当前的查询。

SELECT o.id AS oid, o.date AS date, (i.price*i.qty) AS subtotal FROM orders o, items i WHERE o.cosid=? AND o.id=i.OrderID GROUP BY o.id ORDER BY o.id DESC LIMIT 5;

Answer 1

SELECT o.id AS oid, o.date AS date, SUM(i.price*i.qty) AS total_per_order_date 
  FROM orders o 
INNER JOIN items i 
    ON o.id = i.orderid 
 GROUP BY o.id,o.date 
ORDER BY o.id,o.date ;

Answer 2

您需要将日期添加到GROUP BY子句中，并应用SUM()函数对价格求和：

SELECT o.id AS oid, 
  o.date AS date, 
  SUM(i.price*i.qty) AS subtotal 
FROM orders o, items i 
WHERE o.cosid=? 
  AND o.id=i.OrderID 
GROUP BY o.id,o.date
ORDER BY o.id 
DESC LIMIT 5

Answer 3

尝试使用

sum(i.price*i.qty) as subtotal

否则你只是计算每个项目的结果。

查找订单mysql中所有项目的SUM

3 个答案: