我试图让用户搜索最多6种不同类型的字符串(文本)。但是我已经尝试了最多2个,
问题
但我的代码只对第一个执行正确的搜索。但是,fisrt字符串之后的任何搜索都无法实现目标。
目标
代码的目的是让它在speficied行中找到字符串,然后在coloumn中搜索大于零的值,如果这样的话复制整行。
Private Sub btnUpdateEntry_Click()
Dim StringToFind As String
Dim SringToFind2 As String
Dim i As Range
Dim cell As Range
StringToFind = Application.InputBox("Enter string to find", "Find string")
StringToFind2 = Application.InputBox("Enter string to find", "Find string")
With Worksheets("Skills Matrix")
Set cell = .Rows(1).Find(What:=StringToFind, LookAt:=xlWhole, _
MatchCase:=False, SearchFormat:=False)
If Not cell Is Nothing Then
For Each i In .Range(cell.Offset(1), .Cells(.Rows.Count, cell.Column).End(xlUp))
If IsNumeric(i.Value) Then
If i.Value > 0 Then
i.EntireRow.Copy
Sheets("Data").Range("A" & Rows.Count).End(xlUp).Offset(1, 0).PasteSpecial
End If
End If
Next i
Else
Worksheets("Data").Activate
MsgBox "String not found"
End If
End With
End Sub
谢谢
答案 0 :(得分:1)
不是存储字符串以搜索单独的变量,而是将它们放入数组中。您可以使用For Each
循环遍历数组,因此它非常适合:
Private Sub btnUpdateEntry_Click()
Dim StringsToFind(1 to 6) As String
Dim StringToFind as Variant 'Array's demand that their elements be declared as variants or objects, but we know that the element will be a string
Dim i As Range
Dim cell As Range
'Iterate through your empty array and ask for values:
For Each StringToFind in StringsToFind
StringsToFind(StringToFind) = Application.InputBox("Enter string to find", "Find string")
Next StringToFind
With Worksheets("Skills Matrix")
'Now iterate again to search:
For Each StringToFind in StringsToFinds
Set cell = .Rows(1).Find(What:=StringToFind, LookAt:=xlWhole, _
MatchCase:=False, SearchFormat:=False)
If Not cell Is Nothing Then
For Each i In .Range(cell.Offset(1), .Cells(.Rows.Count, cell.Column).End(xlUp))
If IsNumeric(i.Value) Then
If i.Value > 0 Then
i.EntireRow.Copy
Sheets("Data").Range("A" & Rows.Count).End(xlUp).Offset(1, 0).PasteSpecial
End If
End If
Next i
Else
Worksheets("Data").Activate
MsgBox "String not found"
End If
Next StringToFind
End With
End Sub
可能还有一些其他内部调整用于循环,所以当你迭代时它是有意义的,但这会让你进入大球场。
答案 1 :(得分:1)
类似的解决方案,专为灵活性和速度而设计:
Sub tgr()
Dim wb As Workbook
Dim wsSearch As Worksheet
Dim wsData As Worksheet
Dim rFound As Range
Dim rCopy As Range
Dim rTemp As Range
Dim aFindStrings() As String
Dim vFindString As Variant
Dim sTemp As String
Dim sFirst As String
Dim i As Long, j As Long
Dim bExists As Boolean
Set wb = ActiveWorkbook
Set wsSearch = wb.Sheets("Skills Matrix")
Set wsData = wb.Sheets("Data")
ReDim aFindStrings(1 To 65000)
i = 0
Do
sTemp = vbNullString
sTemp = InputBox("Enter string to find", "Find string")
If Len(sTemp) > 0 Then
bExists = False
For j = 1 To i
If aFindStrings(j) = sTemp Then
bExists = True
Exit For
End If
Next j
If Not bExists Then
i = i + 1
aFindStrings(i) = sTemp
End If
Else
'User pressed cancel or left entry blank
Exit Do
End If
Loop
If i = 0 Then Exit Sub 'User pressed cancel or left entry blank on the first prompt
ReDim Preserve aFindStrings(1 To i)
For Each vFindString In aFindStrings
Set rFound = Nothing
Set rFound = wsSearch.Rows(1).Find(vFindString, wsSearch.Cells(1, wsSearch.Columns.Count), xlValues, xlWhole)
If Not rFound Is Nothing Then
sFirst = rFound.Address
Do
For Each rTemp In wsSearch.Range(rFound.Offset(1), wsSearch.Cells(wsSearch.Rows.Count, rFound.Column).End(xlUp)).Cells
If IsNumeric(rTemp) And rTemp.Value > 0 Then
If rCopy Is Nothing Then
Set rCopy = rTemp.EntireRow
Else
Set rCopy = Union(rCopy, rTemp.EntireRow)
End If
End If
Next rTemp
Set rFound = wsSearch.Rows(1).FindNext(rFound)
Loop While rFound.Address <> sFirst
Else
MsgBox "[" & vFindString & "] not found."
End If
Next vFindString
If Not rCopy Is Nothing Then rCopy.Copy wsData.Cells(wsData.Rows.Count, "A").End(xlUp).Offset(1)
End Sub