Question

在我的Symnfony3项目中，我注意到在注册过程中会生成一些事件，我可以覆盖响应。例如。而不是渲染默认的树枝模板并重定向只返回带有成功消息的JsonResponse。

因此，我做了以下事件订阅者：

namespace AppBundle\EventSubscriber;

use Symfony\Component\EventDispatcher\EventSubscriberInterface;
use FOS\UserBundle\FOSUserEvents;
use FOS\UserBundle\Event\FormEvent;
use AppBundle\Constants\AjaxJsonResponseConstants;
use Symfony\Component\HttpFoundation\JsonResponse;
use FOS\UserBundle\Event\FilterUserResponseEvent;

class UserRegistrationResponseChanger implements EventSubscriberInterface
{
    public static function getSubscribedEvents()
    {
        $subscribedEvents=[
//              FOSUserEvents::REGISTRATION_INITIALIZE=>[],
                FOSUserEvents::REGISTRATION_COMPLETED=>[],
                FOSUserEvents::REGISTRATION_SUCCESS=>["setJsonResponseOnSuccess",-1],
                FOSUserEvents::REGISTRATION_FAILURE=>["setJsonResponseOnFailure",-1],
//              FOSUserEvents::REGISTRATION_CONFIRM=>[],
//              FOSUserEvents::REGISTRATION_CONFIRMED=>[]
        ];
    }

    public function setJsonResponseOnSuccess(FormEvent $formEvent)
    {
        $response=['status'=>AjaxJsonResponseConstants::AJAX_ACTION_SUCCESS,'message'=>"User Sucessfully Registered please check your mail."];
        $response=new JsonResponse($response);
        $formEvent->setResponse($response);

        return $response;
    }

    public function setJsonResponseOnFailure(FormEvent $formEvent)
    {
        $response=['status'=>AjaxJsonResponseConstants::AJAX_ACTION_FAIL,'message'=>"You cannot register please try again later"];
        $response=new JsonResponse($response);
        $formEvent->setResponse($response);

        return $response;
    }
}

同样在我的services.yml上，我提出了以下内容：

 app.user_register.subscriber:
  class: AppBundle\EventSubscriber\UserRegistrationResponseChanger
  tags:
   - { name: app.user_register.subscriber }

命令

为了覆盖响应将如何返回，但不知何故它没有这样做并重定向到默认页面。我尝试通过ajax调用来执行注册，而不是渲染注册页面和重定向。

Answer 1

如果您有注册确认（FOSUserBundle中的默认行为），则应优先考虑REGISTRATION_SUCCESS事件，请参阅http://symfony.com/doc/master/bundles/FOSUserBundle/controller_events.html#registration-success-listener-with-enabled-confirmation-at-the-same-time

服务定义必须如下：

#app/config/services.yml
app.security_registration_success:
    class: Path\To\Your\EventListener\RegistrationSuccessListener
    tags:
        - { name: kernel.event_subscriber }

注册成功监听器的示例：

<?php

declare(strict_types=1);

namespace Path\To\Your\EventListener;

use FOS\UserBundle\Event\FormEvent;
use FOS\UserBundle\FOSUserEvents;
use Symfony\Component\EventDispatcher\EventSubscriberInterface;
use Symfony\Component\HttpFoundation\JsonResponse;

class RegistrationSuccessListener implements EventSubscriberInterface
{
    public static function getSubscribedEvents(): array
    {
        return [FOSUserEvents::REGISTRATION_SUCCESS => [['onRegistrationSuccess', -10]]];
    }

    public function onRegistrationSuccess(FormEvent $event): void
    {
        $event->setResponse(new JsonResponse());
    }
}

Answer 2

您应该执行以下步骤：

首先，当您定义事件订阅者时，您应该使用kernel.event_subscriber而不是app.user_register.subscriber来定义您的订阅者：

 app.user_register.subscriber:
  class: AppBundle\EventSubscriber\UserRegistrationResponseChanger
  tags:
   - { name: kernel.event_subscriber }

致services.yml。

此外，getSubscribedEvents必须返回侦听器的数组。此外，FOSUserEvents::REGISTRATION_COMPLETED 必须如果您不希望侦听器只是评论，那么即使它没有实现，也要有一个监听器。

最后，你的听众应该像这样实施：

namespace AppBundle\EventSubscriber;

use Symfony\Component\EventDispatcher\EventSubscriberInterface;
use FOS\UserBundle\FOSUserEvents;
use FOS\UserBundle\Event\FormEvent;
use AppBundle\Constants\AjaxJsonResponseConstants;
use Symfony\Component\HttpFoundation\JsonResponse;
use FOS\UserBundle\Event\FilterUserResponseEvent;

class UserRegistrationResponseChanger implements EventSubscriberInterface
{
    public static function getSubscribedEvents()
    {
        $subscribedEvents=[
//              FOSUserEvents::REGISTRATION_INITIALIZE=>[],
//              FOSUserEvents::REGISTRATION_COMPLETED=>[],
                FOSUserEvents::REGISTRATION_SUCCESS=>["setJsonResponseOnSuccess",-1],
                FOSUserEvents::REGISTRATION_FAILURE=>["setJsonResponseOnFailure",-1],
//              FOSUserEvents::REGISTRATION_CONFIRM=>[],
//              FOSUserEvents::REGISTRATION_CONFIRMED=>[]
        ];

        return $subscribedEvents;
    }

    public function setJsonResponseOnSuccess(FormEvent $formEvent)
    {
        $response=['status'=>AjaxJsonResponseConstants::AJAX_ACTION_SUCCESS,'message'=>"User Sucessfully Registered please check your mail."];
        $response=new JsonResponse($response);
        $formEvent->setResponse($response);

        return $response;
    }

    public function setJsonResponseOnFailure(FormEvent $formEvent)
    {
        $response=['status'=>AjaxJsonResponseConstants::AJAX_ACTION_FAIL,'message'=>"You cannot register please try again later"];
        $response=new JsonResponse($response);
        $formEvent->setResponse($response);

        return $response;
    }
}

Symfony 3：FOSSUserBundle获取JsonResponse而不是重定向

2 个答案: