Question

我在尝试从命令行运行testng.xml时遇到问题，因为它会自动返回：enter image description here

如果我从eclipse运行testng.xml（ProjectName-＆gt; testng.xml-＆gt; rightClick-＆gt;运行as-＆gt; TestNG套件）一切正常： enter image description here 该类的代码是：`

DataTable dt = new DataTable();
SqlDataReader rdr = cmd.ExecuteReader();
dt.Load(rdr);
dataReader.Close();
Chart1.DataBindTable(dt,"Consumo_Medio_Real");

在命令行中，我执行以下命令：

package TestNGZ;

import io.appium.java_client.android.AndroidDriver;

import java.net.MalformedURLException;
import java.net.URL;


import org.openqa.selenium.By;

import org.openqa.selenium.remote.DesiredCapabilities;
import org.openqa.selenium.support.ui.ExpectedConditions;
import org.openqa.selenium.support.ui.WebDriverWait;
import org.testng.Assert;

import org.testng.annotations.Test;

public class ClassOne {

AndroidDriver dr;

    @Test
    public void call() throws MalformedURLException{

        DesiredCapabilities capabilities = new DesiredCapabilities();
        capabilities.setCapability("deviceName", "Nexus5");
        capabilities.setCapability("platformVersion", "6.0");
        capabilities.setCapability("platformName", "Android");
        capabilities.setCapability("appPackage", "com.age.wgg.appspot");
        capabilities.setCapability("appActivity", "com.age.wgg.appspot.Main");

        dr = new AndroidDriver(new URL("http://127.0.0.1:4723/wd/hub"), capabilities);
    }
    @Test
    public void login() throws InterruptedException {

        String buttonCheckLogIn = "Settings";

        WebDriverWait wait = new WebDriverWait(dr,30);

        //Implicit Wait
    //  dr.manage().timeouts().implicitlyWait(1,TimeUnit.SECONDS); 

        //Explicit Wait
        wait.until(ExpectedConditions.visibilityOfElementLocated(By.xpath("//android.widget.Button[5]")));
        //Tap on FB Login 
        dr.findElement(By.xpath("//android.widget.Button[5]")).click();

        wait.until(ExpectedConditions.visibilityOfElementLocated(By.xpath("//android.widget.EditText[1]")));

        //Insert Username 
        dr.findElement(By.xpath("//android.widget.EditText[1]")).click();
        dr.getKeyboard().sendKeys("waaionel@yahoo.ro");
        //Insert Password
        dr.findElement(By.xpath("//android.widget.EditText[2]")).click();
        dr.getKeyboard().sendKeys("Gameloft2013");
        //Tap on Log In button
        dr.findElementByAccessibilityId("Log In ").click();


        //Explicit Wait
        wait.until(ExpectedConditions.visibilityOfElementLocated(By.xpath("//android.view.View")));
        //Tap OK in Confirmation Prompt
        dr.findElementByAccessibilityId("OK ").click();

        //Explicit Wait
        wait.until(ExpectedConditions.visibilityOfElementLocated(By.xpath("//android.widget.Button[5]")));

        //Verification if the Login was successfully or not
        if (dr.findElement(By.xpath("//android.widget.Button[5]")).getText().equals(buttonCheckLogIn)) {
            System.out.println("Log In ===> Success");
        } else {
        System.out.println("Log In ===> Failed");

        }
    }

    @Test
    public void logout() throws InterruptedException {

        String buttonCheckLogOut = "Log in";

        //Verifying FB Log out functionality 
        dr.findElement(By.xpath("//android.widget.Button[5]")).click();
        dr.findElement(By.name("Logout")).click();
        dr.findElement(By.name("YES")).click();

        Assert.assertTrue(dr.findElement(By.xpath("//android.widget.Button[5]")).getText().equals(buttonCheckLogOut));
        //Verification if the Log out was successfully or not
        if (dr.findElement(By.xpath("//android.widget.Button[5]")).getText().equals(buttonCheckLogOut)) {
            System.out.println("Log Out ===> Success");
        } else {
        System.out.println("Log Out ===> Failed");

        }

        //Kill Session
        dr.quit();
    }
}`

Appium服务器正在运行，Emulator已启用。我已经搜遍了所有，但我没有找到解决方案，也许有人可以帮助我。感谢。

Answer 1

我发现了什么问题。在libs＆＃34; ... \ lib *＆＃34;的路径中它必须是在Eclipse中也使用的所有.JAR，在这种特殊情况下，路径仅用于testng.jar，所以在Projects文件夹中我创建了一个包含Eclipse中所有Jar文件的lib文件夹。感谢。

从命令行运行testng.xml始终返回“Total tests run：0”

1 个答案: