Question

我遇到MySql查询的1个问题：

select sum(h.total_rooms) as total_rooms from reservation_details as rd LEFT JOIN hotels as h ON rd.hotel_id = h.id left join `chains` as `c` on `c`.`id` = `h`.`chain_id` where YEAR(rd.created_at) = 2016 and MONTH(rd.created_at) = 5 and rd.status >= 50 and h.chain_id = 2 GROUP BY rd.hotel_id

以上查询返回：

total_rooms
48216
7700
13250

但是我需要查询的总和。

Answer 1

尝试使用这样的sum（）函数，并在查询中使用ROLLUP。

select sum(h.total_rooms) as total_rooms from reservation_details as rd 
LEFT JOIN hotels as h ON rd.hotel_id = h.id 
left join `chains` as `c` on `c`.`id` = `h`.`chain_id` 
where YEAR(rd.created_at) = 2016 and MONTH(rd.created_at) = 5 
and rd.status >= 50 and h.chain_id = 2 GROUP BY rd.hotel_id 
WITH ROLLUP

Mysql查询 - 问题

1 个答案: