Question

所以，我正在写一个程序，我有一个带有攻击移动的xml文件，我希望用我的值替换损坏值，我已经有了我的值，并附有一个名字，例子是

“滑车| 2D8”

现在，在我的xml文件中，它如下：

<Move>
    <Name>Steamroller</Name>
    <Type>Bug</Type>
    <Frequency>EOT</Frequency>
    <Accuracy>2</Accuracy>
    <Range>Melee</Range>
    <Damage>1d10+10</Damage>
    <Class>Physical</Class>
    <Targets>1 Target, Pass</Targets>
    <Effect>Steamroller Flinches the target on 15-20 during Accuracy Check. If the target is Small, Steamroller deals an additional 1d10.</Effect>
    <ContestType>Tough</ContestType>
    <Appeal>3d4</Appeal>
    <ContestEffect>No Effect</ContestEffect>
    <Special />
  </Move>
  <Move>
    <Name>String Shot</Name>
    <Type>Bug</Type>
    <Frequency>At-Will</Frequency>
    <Accuracy>3</Accuracy>
    <Range>6</Range>
    <Damage />
    <Class>None</Class>
    <Targets>1 Target, Column</Targets>
    <Effect>String Shot creates a Column 2-meters wide. All Legal Targets within the Column lower their Speed 1 Combat Stage. If a target is hit by String Shot 5 times within 5 rounds of combat, they are Trapped. If a target's Speed Combat Stage has already been lowered 6 times, String Shot Traps them.</Effect>
    <ContestType>Smart</ContestType>
    <Appeal>2d4</Appeal>
    <ContestEffect>Excitement</ContestEffect>
    <Special>Threaded</Special>
  </Move>

所以基本上我想要替换<Damage>和</Damage>之间的文本，但我不知道如何解决这个问题，目前我所拥有的是两个数组，其中一个包含我的移动他们的伤害，另一个是Xml文件移动拆分（使用string.Split("</Move>")）然后我循环通过这两个：

for (int index = 0; index < xmlMoves.Length; index++)
        {

            foreach (var move in myMovesArray)
            {
//myMoves.Split('|')[0] is the name of the move, 
    //i'm comparing that the move i am at in my Array is the same as the one in the Array of Xml Moves
                if (xmlMoves[index].Contains(myMoves.Split('|')[0])) 

                {
                    //Replace stuff here
                }
            }
        }

如果有人能提供帮助那就太棒了，谢谢！

Answer 1

你走了！

如评论中所述，您希望将xmlString解析为实际的XML对象，以便您可以轻松访问这些元素。这使用XDocument，因此您需要将using System.Xml.Linq;添加到文件的顶部。

private void XMltest()
{
    string filePath = @"path to your xml";
    string[] myMovesArray = new string[2] {"Steamroller|2d8", "String Shot|4d10"};

    // Add a root to your xml since it wasn't shown in your example
    // NOTE: Remove these next two lines if your xml string does indeed have a root. 
    string xmlFragments = File.ReadAllText(filePath);
    string rootedXML = "<root>" + xmlFragments + "</root>";

    // load the xml
    XDocument xmlMoves = XDocument.Parse(rootedXML);

    // Loop through array and update associated element in xml with the new damage values
    foreach (var move in myMovesArray)
    {
        string moveName = move.Split('|')[0];
        string moveDamage = move.Split('|')[1];

        // Loop through xml and find the correct element by name
        foreach (XElement xmlMove in xmlMoves.Descendants("Move"))
        {
            if (xmlMove.Element("Name").Value == moveName)
            {
                xmlMove.Element("Damage").Value = moveDamage;
            }
        }
    }

    // Save back to xml file.
    xmlMoves.Save(filePath);
}

Answer 2

根据评论，不要使用文本操作来执行此操作。使用LINQ to XML非常简单：

var doc = XDocument.Parse(xml);

foreach (var move in doc.Descendants("Move"))
{
    if ((string) move.Element("Name") == "Steamroller")
    {
        var damage = move.Element("Damage");
        if (damage != null)
        {
            damage.Value = "2d8";
        }
    }
}

有关正常工作的演示，请参阅this fiddle。

Answer 3

您可以使用向后和向前的前瞻进行正则表达式替换：

落后：(?<=(STR_BEFORE)))
转发：(?=(STR_AFTER))

所以，例如(?<=(abc))def(?=(ghi))只有在前面有abc并且后面是ghi

时才会替换def。

删除两个字符串之间的字符串的一部分

3 个答案: