Question

我尝试像这样的查询

Select node.weight * count(ans.cn_gender) as count, ans.cn_gender , poll.pollname
From report.cm_marital_satisfaction ans Join
     poll_management.POLLES poll
     on ans.cn_pollId = poll.id Join
     poll_management.POSITIONS node
     on ans.cn_positionId = node.id
Where ans.cn_pollId in (113)
group by ans.cn_gender, poll.pollname

但是我有错误：ERROR：column＆＃34; node.weight＆＃34;必须出现在GROUP BY子句中或用于聚合函数第1行：选择node.weight * count（ans.cn_gender）作为count，ans.cn_g ... ^ **********错误**********

错误：列＆＃34; node.weight＆＃34;必须出现在GROUP BY子句中或用于聚合函数 SQL状态：42803 性格：8

但我不想在GROUP BY中使用node.weight 请帮帮我

Answer 1

使用具有输出的功能，例如“ MAX（）”或“ MIN（）”：

//TarGzWrite function same as above....
h := new(tar.Header)
//New code after this..
lastIndex := strings.LastIndex(_path, "/tmp")
fmt.Println("String is ", _path, "Last index is", lastIndex)
var name string
if lastIndex > 0 {
    name = _path[lastIndex+len("/tmp")+1:]
    fmt.Println("Got name:", name)
} else {
    //This would not be needed, but was there just for testing my code
    name = _path
}
// h.Name = _path
h.Name = name
h.Size = fi.Size()
h.Mode = int64(fi.Mode())

Answer 2

使用派生表/临时表来获取带有外键的COUNT（ans.cn_gender），然后将其连接到该表以进行乘法运算。这样，您将乘以数字而不是聚合函数。

Answer 3

使用sum()代替count()：

Select sum(node.weight) as count, ans.cn_gender, poll.pollname
From report.cm_marital_satisfaction ans Join
     poll_management.POLLES poll
     on ans.cn_pollId = poll.id Join
     poll_management.POSITIONS node
     on ans.cn_positionId = node.id
Where ans.cn_pollId in (113)
group by ans.cn_gender, poll.pollname

如何在sql中乘以count中的数字字段

3 个答案: