我试图查看第4列中字符串出现的次数。更具体地说,某些Netflow数据中出现端口号的次数。有成千上万的端口,所以除了递归之外,我不会寻找任何特定的东西。我已经使用冒号后面的数字解析了列,我希望代码检查该数字出现的次数,以便最终输出应该打印数字,它出现的次数是这样的..
[OUTPUT]
Port: 80 found: 3 times.
Port: 53 found: 2 times.
Port: 21 found: 1 times.
[CODE]
import re
frequency = {}
file = open('/Users/rojeliomaestas/Desktop/nettest2.txt', 'r')
with open('/Users/rojeliomaestas/Desktop/nettest2.txt', 'r') as infile:
next(infile)
for line in infile:
data = line.split()[4].split(":")[1]
text_string = file.read().lower()
match_pattern = re.findall(data, text_string)
for word in match_pattern:
count = frequency.get(word,0)
frequency[word] = count + 1
frequency_list = frequency.keys()
for words in frequency_list:
print ("port:", words,"found:", frequency[words], "times.")
[FILE]
Date first seen Duration Proto Src IP Addr:Port Dst IP Addr:Port Packets Bytes Flows
2017-04-02 12:07:32.079 9.298 UDP 8.8.8.8:80 -> 205.166.231.250:8080 1 345 1
2017-04-02 12:08:32.079 9.298 TCP 8.8.8.8:53 -> 205.166.231.250:80 1 75 1
2017-04-02 12:08:32.079 9.298 TCP 8.8.8.8:80 -> 205.166.231.250:69 1 875 1
2017-04-02 12:08:32.079 9.298 TCP 8.8.8.8:53 -> 205.166.231.250:443 1 275 1
2017-04-02 12:08:32.079 9.298 UDP 8.8.8.8:80 -> 205.166.231.250:23 1 842 1
2017-04-02 12:08:32.079 9.298 TCP 8.8.8.8:21 -> 205.166.231.250:25 1 146 1
答案 0 :(得分:0)
来自python标准库。将返回一本完全符合您要求的字典。
from collections import Counter
counts = Counter(column)
counts.most_common(n) # will return the most common values for specified number (n)
答案 1 :(得分:0)
您需要以下内容:
frequency = {}
with open('/Users/rojeliomaestas/Desktop/nettest2.txt', 'r') as infile:
next(infile)
for line in infile:
port = line.split()[4].split(":")[1]
frequency[port] = frequency.get(port,0) + 1
for port, count in frequency.items():
print("port:", port, "found:", count, "times.")
这样做的核心是你要保持端口的数字,并为每一行增加。 dict.get
将返回当前值或默认值(在本例中为0)。