Question

我正在为我的WEB API定义新的合同，我想要具有特定的XML格式，以便它可以接受下面的XML，我想将其解析为下面的类类。 JSON格式完全按照我的预期映射，但XML不是。

如何停止在XML中生成“成员”包装器节点？

我想要解析成类的XML：

<MembersUpdate>
<NotificationUrl>http://yoururl/member/profile/</NotificationUrl>
<Timestamp >2017-04-11T12:13:35.6516915Z</Timestamp>
<Member>
    <MemberId>0</MemberId>
    <LastUpdated>0001-01-01T00:00:00</LastUpdated>
</Member>
<Member>
    <MemberId>0</MemberId>
    <LastUpdated>0001-01-01T00:00:00</LastUpdated>
</Member>
<Member>
    <MemberId>0</MemberId>
    <LastUpdated>0001-01-01T00:00:00</LastUpdated>
</Member>
<Member>
    <MemberId>0</MemberId>
    <LastUpdated>0001-01-01T00:00:00</LastUpdated>
</Member>
</MembersUpdate>

映射类：

    /// <remarks/>
[DataContract]
public partial class MembersUpdate
{
    /// <remarks/>
    [DataMember]
    public string NotificationUrl { get; set; }

    /// <remarks/>
    [DataMember]
    public System.DateTime Timestamp { get; set; }

    /// <remarks/>
    [DataMember]
    public MembersUpdateMember[] Member { get; set; }
}

/// <remarks/>
[DataContract]
public partial class MembersUpdateMember
{
    /// <remarks/>
    [DataMember]
    public byte MemberId { get; set; }

    /// <remarks/>
    [DataMember]
    public System.DateTime LastUpdated { get; set; }
}

但是，渲染的示例确实有其他节点，并且无法解析原始XML。我添加了为以下结构渲染的样本：

<MembersUpdate xmlns:i="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://schemas.datacontract.org/2004/07/CivicaSystemsLtd.Areas.Notices.ApiControllers">
      <Member>
        <MembersUpdateMember>
          <LastUpdated>2017-04-11T23:58:06.6310087+01:00</LastUpdated>
          <MemberId>64</MemberId>
        </MembersUpdateMember>
        <MembersUpdateMember>
          <LastUpdated>2017-04-11T23:58:06.6310087+01:00</LastUpdated>
          <MemberId>64</MemberId>
        </MembersUpdateMember>
      </Member>
      <NotificationUrl>sample string 1</NotificationUrl>
      <Timestamp>2017-04-11T23:58:06.6300095+01:00</Timestamp>
    </MembersUpdate>

Answer 1

这几乎是不可能的，因为WebAPI使用DataContractSerializer。

如果您可以切换到XmlSerializer，则可以执行以下操作：

[XmlElement(ElementName = "Member")]
public MembersUpdateMember[] Member { get; set; }

您可以通过attribute on your Controller开启需求：

public class UseXmlSerializerAttribute : Attribute, IControllerConfiguration
{
    public void Initialize(HttpControllerSettings controllerSettings,
                           HttpControllerDescriptor controllerDescriptor)
    {
        var xmlFormater = new XmlMediaTypeFormatter {UseXmlSerializer = true};

        controllerSettings.Formatters.Clear();
        controllerSettings.Formatters.Add(xmlFormater);
    }
}

然后在你的控制器上使用它：

[UseXmlSerializer]
public class FooController : ApiController
{
}

WebAPI将类映射为xml

1 个答案: