将csv导入datagridview过滤器

Question

我的问题是如何过滤列的内容。 我有一个像'Spinbase TrackingState'这样的专栏，我有两个选项'跟踪'和'未跟踪' 我想加载，其中只包括'Tracked'。 谢谢你的帮助！:)

namespace LoadFromCsv
{
public partial class Form1 : Form
{
    public Form1()
    {
        InitializeComponent();
    }
    public DataTable ReadCsv(string filePath)
    {
        var dt = new DataTable();
        List<string> cols = File.ReadLines(filePath).Take(1)
            .SelectMany(x => x.Split(new[] { ';' }))
            .ToList();
        for (int i = 0; i < cols.Count; i++)
        {
            string colName = cols[i].Trim();
            //Debug.Print(colName);
            int num = 1;

            for (int j = i+1; j < cols.Count; j++)
            {
                if (cols[i] == cols[j])
                {
                    //Debug.Print(string.Format("({0},{1})", i, j));
                    cols[j] = string.Format("{0}_{1}", cols[i], ++num);
                    Debug.Print(string.Format("{0} -> {1}", cols[i], cols[j]));
                }
            }

            /*
            while (dt.Columns.Contains(colName))
            {
                Debug.Print(string.Format("{0} -> {1}", num, colName));
                colName = string.Format("{0}_{1}", cols[i], ++num);
                Debug.Print(colName);
            }
            dt.Columns.Add(colName.Trim());
            //cols[i] = colName;
        */        
        }
        cols.ForEach(x => dt.Columns.Add(x.Trim()));

        File.ReadLines(filePath).Skip(1)
            .Select(x => x.Split(';'))
            .ToList()
            .ForEach(line => dt.Rows.Add(line));

        return dt;

    }
    private void button1_Click(object sender, EventArgs e)
    {
        try
        {
            using (OpenFileDialog ofd = new OpenFileDialog() { Filter = "CSV|*.csv", ValidateNames = true, Multiselect = false })
            {
                if (ofd.ShowDialog() == DialogResult.OK)
                    dataGridView1.DataSource = ReadCsv(ofd.FileName);

            }
        }
        catch (Exception ex)
        {
            MessageBox.Show(ex.Message, "Message", MessageBoxButtons.OK, MessageBoxIcon.Error);
        }
    }
}

}