我正在使用此代码过滤多个字段
$fields = array('ageid', 'heightid', 'waistid'); //database fields
$txtfields = array('txtagefrom', 'txtheightfrom', 'txtwaistfrom'); //from range
$txttofields = array('txtageto', 'txtheightto', 'txtwaistto'); // To Range
$conditions = array();
foreach (array_map(NULL, $fields, $txtfields, $txttofields) as $x) {
list($fields, $txtfields, $txttofields) = $x;
echo "'" . $fields . "' between '" . $txtfields . "' And '" . $txttofields . "'";
}
但是我被卡住了,如果某些字段为空,那么它也会显示结果,我尝试了多种方法但是失败了。
我需要,如果这些字段中的任何一个为空,那么它将不会显示在结果上。
请参阅完整代码here
答案 0 :(得分:0)
检查$ fields是否为空或is_null
你的代码中还有一个拼写错误
<input type="text" name="txtwasitto" placeholder="Wasit To" />
将其更改为
<input type="text" name="txtwaistto" placeholder="Wasit To" />
确保从$ _POST
中删除XSS$fields = array('ageid', null, 'heightid', null, 'waistid'); //database fields
$txtfields = array('txtagefrom', 'testnull', 'txtheightfrom', 'testnull', 'txtwaistfrom'); //from range
$txttofields = array('txtageto', 'testnull', 'txtheightto', 'testnull', 'txtwaistto'); // To Range
$conditions = array();
foreach (array_map(NULL, $fields, $txtfields, $txttofields) as $x) {
list($fields, $txtfields, $txttofields) = $x;
if(!empty($_POST[$txtfields]) && !empty($_POST[$txttofields]))
echo "'" . $fields . "' between '" . $_POST[$txtfields] . "' And '" . $_POST[$txttofields] . "'";
}