构建列表查看并从下面的代码开始工作但是突出显示我的asList不被Java识别。有些人可以告诉我哪里出错了。这是在以前的Android工作室版本,但现在不是吗?
package com.example.air rocketapps.listviewdemo;
import android.app.Activity;
import android.os.Bundle;
import android.util.Log;
import android.view.Menu;
import android.view.MenuItem;
import android.view.View;
import android.widget.AdapterView;
import android.widget.ArrayAdapter;
import android.widget.ListView;
import android.widget.Toast;
import java.util.ArrayList;
import static java.util.Arrays.asList;
public class MainActivity extends Activity {
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
ListView friendsListView = (ListView)findViewById(R.id.friendsListView);
final ArrayList<String> myFriends = new ArrayList<String>(**asList**("John", "Paul", "George", "Ringo"));
ArrayAdapter<String> arrayAdapter = new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, myFriends);
friendsListView.setAdapter(arrayAdapter);
friendsListView.setOnItemClickListener(new AdapterView.OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
Toast.makeText(getApplicationContext(), "Hello " + myFriends.get(position), Toast.LENGTH_LONG).show();
}
});
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
// Inflate the menu; this adds items to the action bar if it is present.
getMenuInflater().inflate(R.menu.menu_main, menu);
return true;
}
@Override
public boolean onOptionsItemSelected(MenuItem item) {
// Handle action bar item clicks here. The action bar will
// automatically handle clicks on the Home/Up button, so long
// as you specify a parent activity in AndroidManifest.xml.
int id = item.getItemId();
//noinspection SimplifiableIfStatement
if (id == R.id.action_settings) {
return true;
}
return super.onOptionsItemSelected(item);
}
}
答案 0 :(得分:1)
Arrays.asList()
是一种Fabric方法,因此您不应该使用new ArrayList
只是用
final ArrayList<String> myFriends = Arrays.asList("John", "Paul", "George", "Ringo"));
更新:在分配左侧使用界面更好,即
最终列表&lt;串GT; myFriends
答案 1 :(得分:0)
没有Activity.asList()函数。有一个Arrays.asList()函数。这可能就是你的意思。
答案 2 :(得分:-1)
我这样创建,并且可以正常工作
final ArrayList<String> myfamily = new ArrayList<String>(asList(new String[]{"Rob","Tommy","Ben","Charly"}));
答案 3 :(得分:-1)
我这样创建,并且可以正常工作。 最终列表myFriends = Arrays.asList(“ John”,“ Jane”,“ Anuj”,“ Biubiu”);