无法从String反序列化java.time.LocalDateTime类型的值

时间:2017-04-11 13:09:47

标签: java json spring date spring-boot

我有以下配置:

    @Bean
    @Primary
    public ObjectMapper objectMapper(Jackson2ObjectMapperBuilder builder) {
        ObjectMapper objectMapper = builder.createXmlMapper(false).build();
        objectMapper.configure(SerializationFeature.WRITE_DATES_AS_TIMESTAMPS, false);
//        objectMapper.configure(SerializationFeature.WRITE_DATE_TIMESTAMPS_AS_NANOSECONDS, false);
        return objectMapper;
    }

以及以下依赖项:

ext {
        springBootVersion = '1.5.2.RELEASE'
    }
.... 
dependencies {
    compile('org.springframework.boot:spring-boot-starter-websocket')
    compile("org.springframework:spring-messaging")
    compile('org.springframework.boot:spring-boot-starter-actuator')
    compile('org.springframework.boot:spring-boot-starter-thymeleaf')
    compile('org.springframework.boot:spring-boot-starter-validation')
    compile('org.springframework.boot:spring-boot-starter-web')
    compile group: 'net.jcip', name: 'jcip-annotations', version: '1.0'
    compile ("com.fasterxml.jackson.datatype:jackson-datatype-jsr310")
    testCompile('org.springframework.boot:spring-boot-starter-test')
}

我添加了以下控制器:

@PostMapping("/validation_test")
    public String testValidation(@Valid @RequestBody ClientInputMessage clientInputMessage, BindingResult result) {
        logger.info(Arrays.toString(result.getAllErrors().toArray()));
        return "main";
    }


public class ClientInputMessage {
    @NotEmpty
    private String num1;
    @NotEmpty
    private String num2;
    @Past
    private LocalDateTime date;

如果我像这样传递json:

{
      "num1":"324",
      "num2":123,
      "date":"2014-01-01"
    }

应用程序打印输出:

Failed to read HTTP message: org.springframework.http.converter.HttpMessageNotReadableException: Could not read document: Can not deserialize value of type java.time.LocalDateTime from String "2014-01-01": Text '2014-01-01' could not be parsed at index 10
 at [Source: java.io.PushbackInputStream@1204f40f; line: 4, column: 8] (through reference chain: model.ClientInputMessage["date"]); nested exception is com.fasterxml.jackson.databind.exc.InvalidFormatException: Can not deserialize value of type java.time.LocalDateTime from String "2014-01-01": Text '2014-01-01' could not be parsed at index 10
 at [Source: java.io.PushbackInputStream@1204f40f; line: 4, column: 8] (through reference chain: model.ClientInputMessage["date"])

2 个答案:

答案 0 :(得分:6)

原始答案:

java中的LocalDateTime不接受“2014-01-01”作为有效日期字符串。

其他一些信息:

如果您实际上并不关心日期的类型(LocalDate,OffsetDate,ZonedDate,...),您可以将其设为TemporalAccessor,然后使用DateTimeFormatter::parseBest来解析日期。

<强> P.S。
字符串“2014-01-01T00:00:00”对LocalDateTime

有效

答案 1 :(得分:0)

您可以简单地告诉反序列化器,即使输出为LocalDate,也应该是LocalDateTime,请注意为LocalDate设置替代设置器变体

类似:

@JsonDeserialize(as = LocalDate.class)
@Past
private LocalDateTime date;

public void setDate(LocalDateTime input) {
    date = input;
}

public void setDate(LocalDate input) {
    date = input.atStartOfDay();
}