Question

我正在尝试在付款页面上显示付款表信息。

payments{student_id, course_id, payment_type_id}
students{id, name} 
courses{id, name} 
payment_types{id,name}

对于列＆gt; course_id（在付款表中）它显示了付款页面中的课程名称。但是对于其他两列，它没有发布。我的错误是什么。谢谢你提前！

这是我的 Payment.php 模型

protected $fillable = [
    'student_id',
     'course_id',
     'payment_types_list_id',
];

protected $filter = [
   'page' => false,
   '_token' => false,
   'student_id' => '=',
   'course_id'  => '=',
   'payment_types_list_id' => '=',
];

public function Payment() {
    return $this->hasOne('App\Payment');
}

public function course() {
   return $this->belongsTo('App\Course');
}

public function students() {
    return $this->belongsToMany('App\Student');
}

public function PaymentType() {
   return $this->belongsTo('App\PaymentType');
}

这里 payments_table

 public function up() {
      Schema::create('payments', function(Blueprint $table)
      {
          $table->increments('id');
          $table->integer('student_id')->unsigned()->index();
          $table->foreign('student_id')->references('id')->on('students');
          $table->integer('course_id')->unsigned()->index();
          $table->foreign('course_id')->references('id')->on('courses');
          $table->integer('payment_types_list_id');
          $table->foreign('payment_types_list_id')
                ->references('id')->on('payment_types_list');
          $table->timestamps();
      });
 }

这是 PaymentController.php

public function index(Request $request) {
        $filter = $request->input();
        $sort = $request->query();
        $payments = Payment::filter($filter)->sort($sort)->paginate(10);
        foreach(PaymentType::all() as $payment_type) {
            $payment_types[$payment_type->id] = $payment_type->name;
        }
        foreach(Course::all() as $course) {
            $courses[$course->id] = $course->name;
        }
        foreach(Student::all() as $student) {
            $students[$student->id] = $student->name;
        }
        return view('payments.index', compact('payments', 'filter','courses','students', 'payment_types'));
    }

这是 Payment / index.php

@forelse ($payments as $key => $payment)
   <tr>
      <td>{{ ++$key }}</td>
      <td>{{ $payment->student['name'] }}</td>
      <td>{{ $payment->course['name']}}</td>
      <td>{{$payment->payment_types_list['name']}}</td> 
   </tr> 
@endforelse

Answer 1

所以问题在于关系的名称。定义关系时，应使用相同的定义名称访问它。

例如 -

如果您的关系名称为PaymentType，那么您应该访问以下关系：

{{ $payment->PaymentType->name }}

OR

{{ $payment->PaymentType['name'] }}

对于学生关系，它应该是belongsTo而不是belongsToMany所以 -

public function student()
{
    return $this->belongsTo('App\Student');
}

然后您可以按以下方式访问它：

{{ $payment->student->name }}

Docs

如何获取与其他表的元素id和帖子相关的另一个表的记录？

1 个答案: