模型
function Updateno($user,$data){
$this->db->where('username', $user);
$this->db->update('user', $data);
}
控制器
//user login function
function Ulogin(){
if($this->session->userdata('user'))
{
$data['user'] = $this->session->userdata('user');
$this->load->view("User/choosecategory",$data);
}
else
{
$data = array(
'username' =>$this->input->post('username'),
'password' =>$this->input->post('password'),
);
$this->form_validation->set_rules('username','UserName','required');
$this->form_validation->set_rules('password','Password','required');
if($this->form_validation->run()==false)
{
$this->load->view('User/login');
}
else
{
if($this->user_model->userlogin($data)==false)
{
$data['error'] = '<div class="alert alert-danger text-danger">Please Provide Valid Username/Password!</div>';
$this->load->view('User/login',$data);
}
else
{
$this->session->set_userdata('user',$data['username']);
$data['user'] = $this->session->userdata('user');
$counter = array(
'logged_in' =>'logged_in'+1
);
$this->user_model->Updateno($this->session->userdata('user'),$counter);
$this->load->view("User/choosecategory",$data);
}
}
}
}
我希望每当用户登录成功时,我的logged_in cloumn值增加1,但在此代码中,logged_in列的值始终为1,plz帮助我这里的任何人
答案 0 :(得分:2)
这里你唯一需要做的就是将值增加1
尝试以下代码
你的模特
function Updateno($user)
{
$this->db->where('username', $user);
$this->db->set("logged_in","logged_in+1",false);
$this->db->update('user');
}
并在您的控制器中
$this->user_model->Updateno($this->session->userdata('user'));
答案 1 :(得分:0)
你想要做的是:
$value = explode("logged_in", $counter['logged_in']); //get the number of the counter
$counter['logged_in'] = 'logged_in' . ((int)$value[1] +1); //increase value by 1
这将从您的字符串中获取当前计数器值并将其增加1
我做了一个演示来展示如何使用它
DEMO: https://eval.in/773121