Question

我需要制作以下结构：

 "rows":[  
    {//panel1  
    },  
    {//panel2  
    }  
    {//panel3 ...   
    }  
  ]

所以我创建了方法extend，所以我试图这样做，但它不起作用，因为它只返回我最后一个JSON：

var panel_cpu = {"title": "iNeedHelp","smt": 5}
                 
var panel_swap = {"title": "iNeedHelp2","smt":  6}
                 
var combined = $.extend({}, panel_cpu, panel_swap); 

//following the comments...

var arr = [];
arr.push(panel_cpu);
arr.push(panel_swap);     
////////////////////////////     

//following 1 answer
var combined2 = $.extend({}, [panel_cpu, panel_swap]);
//////////////////////////////////////////////////////
var big_panel = {"rows": arr}

console.log(big_panel);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

这里使用的是JQuery，因为我没有找到下划线库

Answer 1

您可以按如下方式实现输出：

var panel_cpu = [{
  "title": "iNeedHelp",
  "smt": 5
}]

var panel_swap = [{
  "title": "iNeedHelp2",
  "smt": 6
}]

var combined = panel_cpu.concat(panel_swap);

var big_panel = [{
  "rows": [combined]
}]

console.log(big_panel);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

但是，您需要拥有panel_cpu和panel_swqp变量的数组值。我会发布一个简单的答案。

修改1

更改此选项将获得如下输出，

var big_panel = {
  "rows": combined
}

var panel_cpu = [{
  "title": "iNeedHelp",
  "smt": 5
}]

var panel_swap = [{
  "title": "iNeedHelp2",
  "smt": 6
}]

var combined = panel_cpu.concat(panel_swap);

var big_panel = {
  "rows": combined
}

console.log(big_panel);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

如何将两个JSON与extend结合并返回它们？

1 个答案: