enqueue okhttp3无法解析方法java

时间:2017-04-11 01:51:49

标签: java android twilio okhttp

我在使用2因素身份验证创建应用时遇到了一些麻烦。我决定使用twilio作为我的短信网关,并决定继续他们的教程。然而,尽管已经导入了我需要的东西,但我遇到了无法解决的入队问题。

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    data = filter(data, s);
    adapter.notifyDataSetChange();

我的build.gradle

import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.Toast;
import android.content.Context;
import java.io.IOException;
import okhttp3.Call;
import okhttp3.Callback;
import okhttp3.FormBody;
import okhttp3.OkHttpClient;
import okhttp3.Request;
import okhttp3.RequestBody;
import okhttp3.Response;

public class MainActivity extends AppCompatActivity {

private EditText mTo;
private EditText mBody;
private Button mSend;
private OkHttpClient mClient = new OkHttpClient();
private Context mContext;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    mTo = (EditText) findViewById(R.id.txtNumber);
    mBody = (EditText) findViewById(R.id.txtMessage);
    mSend = (Button) findViewById(R.id.btnSend);
    mSend.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            try {
                post(mContext.getString(Integer.parseInt("http://4a61510d.grok.io/sms")), new  Callback(){

                    @Override
                    public void onFailure(Call call, IOException e) {
                        e.printStackTrace();
                    }

                    @Override
                    public void onResponse(Call call, Response response) throws IOException {
                        runOnUiThread(new Runnable() {
                            @Override
                            public void run() {
                                mTo.setText("");
                                mBody.setText("");
                                Toast.makeText(getApplicationContext(),"SMS Sent!",Toast.LENGTH_SHORT).show();
                            }
                        });
                    }
                });
            } catch (IOException e) {
                e.printStackTrace();
            }
        }
    });
    mContext = getApplicationContext();
}
Call post(String url, Callback callback) throws IOException {
    RequestBody formBody = new FormBody.Builder()
            .add("To", mTo.getText().toString())
            .add("Body", mBody.getText().toString())
            .build();
    Request request = new Request.Builder()
            .url(url)
            .post(formBody)
            .build();
    Call response = mClient.newCall(request);
    Response.**enqueue**(callback);
    return response;
}}

和我的清单xml

 dependencies {
compile fileTree(dir: 'libs', include: ['*.jar'])
androidTestCompile('com.android.support.test.espresso:espresso-core:2.2.2', 
 {
    exclude group: 'com.android.support', module: 'support-annotations'
})
testCompile 'junit:junit:4.12'
compile 'com.android.support:appcompat-v7:25.3.1'
compile 'com.android.support.constraint:constraint-layout:1.0.2'
compile 'com.squareup.okhttp3:okhttp:3.6.0'

我已经尝试清理构建并在使缓存失效后重新启动。任何帮助,将不胜感激。

2 个答案:

答案 0 :(得分:0)

响应没有静态方法入队,因此尽管已导入,但无法解析。您需要使用对象响应。

Call response = mClient.newCall(request);
response.enqueue(callback);
return response;

答案 1 :(得分:0)

试试这个

response.enqueue(callback);
return response;