Question

我有一个名为senttest.php的php文件。我想要做的是将一个变量从php发送到javascript，以便通过情绪分析工具运行它，然后将其发回到同一文件中的php。我可以把所有的东西都当作必要的工作，除了回复到php，当我回应它时，它会变空。我做错了什么想法或明显的想法？谢谢！

    <?php

    ?>
    <html>
    <head>
    <script src="//ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js">
    </script>

    </head>
    <body>




    <?php

     $full = 'Congratulations to our great military men and women for 
     representing the United States, and the world, so well in the Syria 
     attack.';
     ?>
     <script type="text/javascript">var r1 = "<?= $full ?>";
     var returntext = "";</script>
     <script src="sentiment/bundle.js" type="text/javascript"></script>

     <script type="text/javascript">
     $.ajax({
     url: 'senttest.php', //This is the current doc
     type: "POST",
     dataType:'json', // add json datatype to get json
     data: ({returned: returntext}),
     success: function(data){
         console.log(data);
     }
     });
      document.write(returntext);

     document.write('done with send');


    </script>


<?php

$jsongrab = $_POST['returned'];



$json = json_decode($jsongrab, true);
?>
<p><?php echo $jsongrab ?></p>
<p><?php echo $json['comparative']; ?></p>
</body>
</html>

Answer 1

这不会像现在这样运作。 AJAX调用不适用于此，因为它不会显示提取的HTML。你想要的是一个带有post参数的重定向。使用Rakesh Pai的片段：

function post(path, params, method) {
    method = method || "post"; // Set method to post by default if not specified.

    // The rest of this code assumes you are not using a library.
    // It can be made less wordy if you use one.
    var form = document.createElement("form");
    form.setAttribute("method", method);
    form.setAttribute("action", path);

    for(var key in params) {
        if(params.hasOwnProperty(key)) {
            var hiddenField = document.createElement("input");
            hiddenField.setAttribute("type", "hidden");
            hiddenField.setAttribute("name", key);
            hiddenField.setAttribute("value", params[key]);

            form.appendChild(hiddenField);
         }
    }

    document.body.appendChild(form);
    form.submit();
}

然后在设置returntext时调用post('senttest.php',{returned:returntext},'POST')。

在一个文件中从Javascript发布到PHP

1 个答案: