Question

这应该很简单，但我没有得到预期的结果。浏览器会列出数组中的所有元素（当我包含＆＃34;！＆＃34;运算符时）或者不列出任何元素（当我不包含＆＃34;！时）＆＃34;运营商）。我只想尝试列出除一个元素以外的所有内容或仅列出一个元素。我无法通过任何一种方式工作。

    $features = array(
    'winter' => 'Beautiful arrangements for any occasion.',
    'spring' => 'It must be spring! Delicate daffodils are here.',
    'summer' => "It's summer, and we're in the pink.",
    'autumn' => "Summer's over, but our flowers are still a riot of colors."
    );

    <h1>Labeling Array Elements</h1>
    <?php 
    foreach ($features as $feature) {
    if(array_key_exists('autumn', $features)) { 
    continue;
   } 
   echo "<p>$feature</p>";
   }    
   ?>

Answer 1

当你在循环中执行continue只是因为它存在于数组中时，它会在第一次迭代时停止。这总是如此。

相反，你需要做这样的事情：

foreach ($features as $season => $description) {
    if ($season == 'autumn') {
        continue;
    }
    echo $description;
}

Answer 2

你也可以使用array_filter来实现这种方法：

$features = array(
    'winter' => 'Beautiful arrangements for any occasion.',
    'autumn' => "Summer's over, but our flowers are still a riot of colors.",
    'spring' => 'It must be spring! Delicate daffodils are here.',
    'summer' => "It's summer, and we're in the pink.",
);

print_r(array_filter($features, function ($key) {
    return $key != 'autumn';
}, ARRAY_FILTER_USE_KEY));

现场演示：https://3v4l.org/Ctn8O

列出除关联数组中的一个键之外的所有键

2 个答案: