Question

我有以下JSON

{
  "eventSummaryList": [
    {
      "customer": "189256",
      "data": "{\"cliente\":\"189256\",\"data_posicao\":\"1491426372\",\"gps_valido\":\"1\",\"horimetro\":\"120561\",\"ibuttonHex\":\"0\",\"ibuttonPart1\":\"0\",\"ibuttonPart2\":\"0\",\"id_evento\":\"null\",\"id_motorista\":\"0\",\"ignicao\":\"1\",\"latitude\":\"-2222222\",\"longitude\":\"-2222222\",\"odometro\":\"253692\",\"pos_memoria\":\"0\",\"veiculo\":\"44444\",\"velocidade\":\"50\"}",
      "identifierEventRule": "77404",
      "identifierRule": "6",
      "identifierSummary": "28901976",
      "rule": "velocidade_maior_que",
      "status": 1,
      "vehicle": "44444"
    }
  ],
  "header": {
    "mensagem": {
      "estilo": "SUCCESS",
      "mensagem": "Successfully executed service",
      "plataforma": "EVENT_POINT",
      "status": "SUCESSO"
    }
  }
}

我需要提取值“velocidade”里面的“数据” 包含另一个json。

我使用以下语法，但它返回null。

select  cast((value::json ->'data')::json->> 'velocidade' AS   int)    AS velocidade,

Answer 1

尝试：

<link href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css" rel="stylesheet" integrity="sha384-BVYiiSIFeK1dGmJRAkycuHAHRg32OmUcww7on3RYdg4Va+PmSTsz/K68vbdEjh4u" crossorigin="anonymous">
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.6.3/angular.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/angular-ui-bootstrap/2.5.0/ui-bootstrap-tpls.js"></script>
<body ng-app="MyApp">
<div ng-controller="bodyController">
    <!-- This html would live at the path specified in the controller: path/to/your/modal-template.html -->
        <button style="margin:20px" class="btn" ng-click="open()">Open Modal</button>

    

    </div>
</body>

（SELECT ((value::json #>> '{eventSummaryList,0,data}')::json ->> 'velocidade')::int或#>>运算符是关键。如果您使用->>或#>，您最终会得到一个json编码的json字符串BTW这真的是一个混乱的模型，我会先考虑修改它的输入。）

http://rextester.com/THVYFK9026

选择json中的值到其他json（Postgres）

1 个答案: