如何在一个显示中合并Sql两个sql查询结果显示合并

Question

我想在一个屏幕上并排合并sql查询结果

示例：

Barcode1    Barcode2
888            33

有可能吗？

非常感谢你。

SELECT BARCODE AS BARCODE2  
FROM LG_001_UNITBARCODE, LG_001_ITEMS
WHERE ITEMREF = LG_001_ITEMS.LOGICALREF 
  AND ITEMREF= 17 AND LINENR = 2;


SELECT BARCODE AS BARCODE3 
FROM LG_001_UNITBARCODE, LG_001_ITEMS 
WHERE ITEMREF = LG_001_ITEMS.LOGICALREF 
  AND ITEMREF= 17 AND LINENR = 3;

Answer 1

一种方法是使用如下的子选择：

SELECT BARCODE AS BARCODE2 ,
        (
            SELECT BARCODE AS BARCODE3 
            FROM LG_001_UNITBARCODE, LG_001_ITEMS 
            WHERE ITEMREF = LG_001_ITEMS.LOGICALREF 
                AND ITEMREF= 17 AND LINENR = 3
        ) as BARCODE3
FROM LG_001_UNITBARCODE, LG_001_ITEMS
WHERE ITEMREF = LG_001_ITEMS.LOGICALREF 
AND ITEMREF= 17 AND LINENR = 2;

Answer 2

如果我们可以假设如果存在多行并且每个表的结果数量不同（一个返回3个记录，另外5个）并且它们应该与每个表的条形码顺序相关... 我们可以使用2个公用表表达式和一个row_number（）分析。这样，如果确实存在多行，那么它们都是基于分配的行号相关的，如果一个结果集的行数多于另一个，则会出现空值。

然而，如果它是1-1，那么这仍然有用。

WITH A as (SELECT BARCODE AS BARCODE2, row_number() over (order by barcode) RN 
           FROM LG_001_UNITBARCODE, LG_001_ITEMS
           WHERE ITEMREF = LG_001_ITEMS.LOGICALREF 
             AND ITEMREF= 17 
             AND LINENR = 2),
     B as (SELECT BARCODE AS BARCODE3, row_number() over (order by barcode) RN 
           FROM LG_001_UNITBARCODE, LG_001_ITEMS 
           WHERE ITEMREF = LG_001_ITEMS.LOGICALREF 
             AND ITEMREF= 17 
             AND LINENR = 3)

SELECT A.Barcode2, B.Barcode3 
FROM A
FULL OUTER JOIN B 
 on A.RN = B.RN
;

Row_number（）RN为我们提供了一种将条形码asc序列中的表关联起来的方法。如果一个数据集的记录多于另一个数据集，则完整的外部联接允许我们处理。