我不知道它何时发生,因为在我开发时我在浏览器中启动了会话,因此我不必再通过Google或Facebook登录提供商。当新用户尝试在我的网络应用程序中登录时,她告诉我发生了错误。因此,当浏览器尝试打开Google或Facebook登录弹出窗口时,我清理了浏览器数据并开始显示消息A network error (such as timeout, interrupted connection or unreachable host) has occurred.
。它不会在Safari或我的Android Chrome中发生。
以下是代码段作为参考。
<!--
@license
Copyright (c) 2016 The Polymer Project Authors. All rights reserved.
This code may only be used under the BSD style license found at http://polymer.github.io/LICENSE.txt
The complete set of authors may be found at http://polymer.github.io/AUTHORS.txt
The complete set of contributors may be found at http://polymer.github.io/CONTRIBUTORS.txt
Code distributed by Google as part of the polymer project is also
subject to an additional IP rights grant found at http://polymer.github.io/PATENTS.txt
-->
<link rel="import" href="../bower_components/polymer/polymer.html">
<link rel="import" href="../bower_components/paper-button/paper-button.html">
<link rel="import" href="../bower_components/polymerfire/polymerfire.html">
<link rel="import" href="shared-styles.html">
<dom-module id="my-view1">
<template>
<style include="shared-styles">
:host {
display: block;
padding: 10px;
}
</style>
<div class="card">
<div class="circle">1</div>
<paper-button on-tap="login">Login</paper-button >
<h1>View One</h1>
<p>Ut labores minimum atomorum pro. Laudem tibique ut has.</p>
<p>Lorem ipsum dolor sit amet, per in nusquam nominavi periculis, sit elit oportere ea.Lorem ipsum dolor sit amet, per in n#
</div>
</template>
<script>
Polymer({
is: 'my-view1',
login: function(){//{{{
firebase.initializeApp({
apiKey: apiKey,
authDomain: authDomain,
databaseURL: databaseURL
});
var provider = new firebase.auth.FacebookAuthProvider();
firebase.auth().signInWithPopup(provider).then(function(result){
console.log(result);
}).catch(function(error){
console.error( error);
});
},//}}}
});
</script>
</dom-module>
答案 0 :(得分:0)
我认为您应该在有人点击登录之前初始化应用程序。
('70S ribosome','ALK tyrosine kinase receptor','ATP','ATP synthase)'
('70S ribosome','ALK tyrosine kinase receptor','ATP','ATP synthase)'
每当有人登陆页面时,也许是最好的地方。
答案 1 :(得分:0)
我转到chrome://settings/content/cookies并点击全部删除。这为我解决了。