Question

这是我的代码：

<form method="post" enctype="multipart/form-data">{% csrf_token %}

<input type="file" name="myfile">
<button type="submit">Upload</button>
</form>

{% if uploaded_file_url %}
<p>File uploaded at: <a href="{{ uploaded_file_url }}">{{ uploaded_file_url }}</a></p>
{% endif %}

如何在Django项目中添加文件并将其保存在应用程序的媒体目录中？

Answer 1

来自https://simpleisbetterthancomplex.com/tutorial/2016/08/01/how-to-upload-files-with-django.html的

view.py应该适合您！

def simple_upload(request):
    if request.method == 'POST' and request.FILES['myfile']:
        myfile = request.FILES['myfile']
        fs = FileSystemStorage()
        filename = fs.save(myfile.name, myfile) # saves the file to `media` folder
        uploaded_file_url = fs.url(filename) # gets the url
        return render(request, 'core/simple_upload.html', {
            'uploaded_file_url': uploaded_file_url
        })
    return render(request, 'core/simple_upload.html')

Answer 2

Django文档中包含

File Uploads。

根据您是否尝试将文件上传到Model或FileField的{{1}}，或者您只是想上传，会有轻微差异使用ImageField类的服务器上不属于任何模型的文件。

请注意，Django有一个Form类（Docs），可帮助您生成表单并通过验证处理Form请求等。使用此类而不是编写自己的HTML代码。

无模型上传文件（Docs）

POST

使用模型（Docs）上传文件

# forms.py
from django import forms

class UploadFileForm(forms.Form):
    title = forms.CharField(max_length=50)
    file = forms.FileField()

# views.py
from django.http import HttpResponseRedirect
from django.shortcuts import render
from .forms import UploadFileForm

def handle_uploaded_file(f):
    with open('some/file/name.txt', 'wb+') as destination:
        for chunk in f.chunks():
            destination.write(chunk)

def upload_file(request):
    if request.method == 'POST':
        form = UploadFileForm(request.POST, request.FILES)
        if form.is_valid():
            handle_uploaded_file(request.FILES['file'])
            return HttpResponseRedirect('/success/url/')
    else:
        form = UploadFileForm()
    return render(request, 'upload.html', {'form': form})

文件在django中上传

2 个答案:

无模型上传文件（Docs）

使用模型（Docs）上传文件