Question

这是表格：

class APIBackoffInterrupt(Base):
    """
    When a user calls a Google API method, and it returns 403 or 429, we should apply an exponential backoff
    """
    __tablename__ = 'backoff_interrupt'
    _id = Column(Unicode(36), primary_key=True)
    user_id = Column(Unicode(36))
    date_created_utc = Column(DateTime)
    expiry_date_utc = Column(DateTime, nullable=True)
    exponent = Column(Integer, default=-1)

我想获得所有唯一的user_id，按date_created_utc（desc）排序，其中expiry_date_utc是＆lt;现在的utc。

我该怎么做？

Answer 1

select distinct user_id 
 from backoff_interrupt
   where expiry_date_utc <getdate() 
 order by date_created_utc desc

检查一下：更新：

select * into #temp from backoff_interrupt  
 where expiry_date_utc <getdate()
 order by date_created_utc desc 

  select distinct user_Id from #temp

 drop #temp

Answer 2

    q1 = (session.query(APIBackoffInterrupt,
                        func.rank().over(order_by=desc(APIBackoffInterrupt.date_created_utc),
                                         partition_by=APIBackoffInterrupt.user_id).label('rnk'))
          ).subquery()
    q2 = (session.query(q1)
          .filter(q1.c.rnk == 1)
          .filter(q1.c.expiry_date_utc < datetime.datetime.utcnow())
          )

如何在一列上有group_by，在另一列上有order_by，在第三列上有过滤器？

2 个答案: