Question

我需要一个帮助。我需要检查一个表的列数据是否存在于使用PHP和MySQL的同一数据库中的另一个表中。我正在解释下面的表。

db_gallery：

id       subcat_id         image

1           60             123.png

2           60             234.png

3           58             456.png

db_special_image

id      subcat_id         name        gallery_image

 1         60              aaa          123.png

 2         58              bbb          456.png

在这里，我需要检查db_special_image表中是否存在任何图库图像。我需要查看subcat_id。假设我知道subcat_id=60。我需要检查db_gallery表中属于subcat_id=60的{{1}}表中的任何图像是否存在于db_special_image表中。如果有任何图像，那么它将返回1否则为0.我需要查询。请帮帮我。

Answer 1

您可以使用Mysql INNER JOIN加入两个表格。然后使用count（＆＃39;某事＆＃39;）; if it's !=0, echo "1"; else echo "0"

See this tutorial

Answer 2

显示db_gallery中存在的图像以及db_special_image ...

内部查询错误？

SELECT * from db_gallery WHERE db_gallery.image IN (SELECT gallery_image FROM db_special_image WHERE db_gallery.subcat_id = db_special_image.subcat_id)

<强>加入

SELECT * from db_gallery INNER JOIN db_special_image ON db_gallery.subcat_id = db_special_image.subcat_id AND db_gallery.image=db_special_image.gallery_image

Answer 3

使用x2 = x[np.ix_(np.arange(x.shape[0]), k.flat, i.flat, j.flat)].reshape((x.shape[0], ) + k.shape + i.shape + j.shape) x2.shape (2, 12, 1, 12, 25, 12, 25) np.all(x1 == x2) True INNER JOIN关键字选择两个表中具有匹配值的记录。 mysql INNER JOIN

ON db_gallery.subcat_id = db_special_image.subcat_id

如果num_rows count大于0 SELECT name,db_gallery.subcat_id,image from db_gallery INNER JOIN db_special_image ON db_gallery.subcat_id = db_special_image.subcat_id

其他echo "1";

如何使用PHP和MySQL比较两个表

3 个答案: