I have read the documentation and I am able to display the table on my page, but how would I make each row clickable and using a GET request, send the requested data to another page after clicking on a row? I have read other questions on SO, but can't seem to find a solution that would work for me. This is what I have so far. Thank you for any help and effort!
<table cellpadding="1" cellspacing="1" id="scroll">
<thead>
<th>Name</th>
<th>Address</th>
<th>Age</th>
</thead>
<tfoot>
<tr>
<th>Name</th>
<th>Address</th>
<th>Age</th>
</tr>
</tfoot>
<tbody>
<tr>
<td> Placeholder1</td>
<td> Placeholder2</td>
<td> Placeholder3</td>
</tr>
<tr>
<td> Placeholder1</td>
<td> Placeholder2</td>
<td> Placeholder3</td>
</tr>
<tr>
<td> Placeholder1</td>
<td> Placeholder2</td>
<td> Placeholder3</td>
</tr>
</tbody>
</table>
<script>
$(document).ready(function(){
var table = $('#scroll').dataTable( { "sPaginationType": "full_numbers" } );
$('#scroll tbody').on('click', 'tbody tr', function(){
var data = table.row(this).data();
console.log(data);
})
});
答案 0 :(得分:1)
JQUERY part:
$(document).off( "click", "#scroll tbody tr").on( "click", "#scroll tbody tr", function(){
var i = 0;
var query = "";
$(this).find("td").each(function(){
query += "columns[" + i++ + "]=" + $(this).text + "&";
})
$.ajax({
type: "POST",
url: "script.php",
data: query,
success: function(){
alert ("Successfully sent");
}
})
})
PHP part (script.php)
<?php
$columns = $_POST["columns"];
foreach ($columns as $index => $value)
{
// do something with column # $index and text value is $value
}
?>
答案 1 :(得分:0)
var data = table.row(this).data();
这会返回行对象,因此您需要更改
console.log(data);
至
console.log(data[0] + " " + data[1] + " " + data[2]);
答案 2 :(得分:0)
我发现mmushtaq将文档链接到我需要的地方。这使得行现在可以点击。谢谢