Question

我有一个非常简单的Mac应用程序，在某个特定时间，一个按钮会显示带有输入字段的NSAlert。之后，我在NSTableView上采取了一些操作。如果用户按下OK按钮，它可以正常工作，但如果用户按下ENTER，则不会定义选定的

 NSAlert *alert = [[NSAlert alloc] init];
[alert setMessageText:@"Damage"];
[alert addButtonWithTitle:@"Ok"];
[alert addButtonWithTitle:@"Cancel"];
NSInteger damage = 0;
NSTextField *input = [[NSTextField alloc] initWithFrame:NSMakeRect(0, 0, 200, 24)];
[input setStringValue:@""];
[[alert window]setInitialFirstResponder:input];

[alert setAccessoryView:input];
NSInteger button = [alert runModal];
if (button == NSAlertFirstButtonReturn) {
     damage = [input integerValue];
} else if (button == NSAlertSecondButtonReturn) {

}

//data
NSIndexSet *set = [self.tableView selectedRowIndexes];

NSUInteger index = [set lastIndex];

索引的值为NSNotFound。

有人可以帮忙解决吗？ TKS

Answer 1

所以，我基本上需要添加一个等同于ENTER的键，它解决了这个问题：

 NSAlert *alert = [[NSAlert alloc] init];
[alert setMessageText:@"Damage/Heal"];
[alert addButtonWithTitle:@"Ok"];
[alert addButtonWithTitle:@"Cancel"];
NSInteger damage = 0;
NSTextField *input = [[NSTextField alloc] initWithFrame:NSMakeRect(0, 0, 200, 24)];
[input setStringValue:@""];
[[alert window]setInitialFirstResponder:input];

[alert setAccessoryView:input];
alert.buttons[0].keyEquivalent=@"\r";//new code
NSInteger button = [alert runModal];
if (button == NSAlertFirstButtonReturn) {
    damage = [input integerValue];
} else if (button == NSAlertSecondButtonReturn) {

}

当用户在NSAlert之后按Enter键时，NSIndexSet未设置

1 个答案: