Question

我需要为不同的phiStart和phiExit值填充一个包含90个元素周期的360元素矩阵：

flute    = 4;
phiStart = 0;
phiExit  = 90;
phiDelta = 1;
phiPitch = 360 / flute;

for g = 0:abs(phiExit - phiStart);
    for k = 0:abs(phiExit - phiStart);
        for j = 0:abs(phiExit - phiStart);
            for m = 0:abs(phiExit - phiStart);
                for i = 0:abs(phiExit - phiStart);
                    answerA = phiStart + i * phiDelta;
                    phi(i+1) = answerA;
                end
                answerA = phiStart + m * phiDelta;
                phi(m + phiPitch) = answerA;
            end
            answerA = phiStart + j * phiDelta;
            phi(j + 2 * phiPitch) = answerA;
        end
        answerA = phiStart + k * phiDelta;
        phi(k + 3 * phiPitch) = answerA;
    end
    answerA = phiStart + g * phiDelta;
    phi(g + 4 * phiPitch) = answerA;
end

b = (phi > 0);  % dummy matrix for edge cofficients
h = feedRate * sin(phi / 180 * pi);

Answer 1

很抱歉，如果这没有意义（只是想提供帮助），我甚至不知道它是用什么语言编写的，但我在原始代码中读到的内容指的是

for i = 0:abs(phiExit - phiStart);
    answerA = phiStart + i * phiDelta;
    for j = 0:abs(flute - 1)
        phi(i + j * phiPitch) = answerA;
    end
end

我怎样才能简化循环？

1 个答案: