Question

我在将CSV文件上传到MySQL数据库时遇到问题。我不是一个非常有经验的编码员，所以如果我试图解决这个问题的方法已经过时了，那我很抱歉，但是我将包括我到目前为止所尝试的内容。

以下是代码的HTML部分：

<form enctype="multipart/form-data" action="camperUpload.php" method="POST">
<input type="hidden" name="MAX_FILE_SIZE" value="100000" />
Choose a file to upload: <input name="uploadedfile" type="file" /><br />
<input type="submit" value="Upload File" class="btn btn-border" />
</form>

这是PHP部分：

function processFile($uploadedFile) {



    // file contents
    $file_contents = $uploadedFile["tmp_name"];

    $SQL_statement = "LOAD DATA LOCAL INFILE '$file_contents' INTO TABLE C_CAMPER FIELDS TERMINATED BY ','
                        LINES TERMINATED BY '\n' IGNORE 3 LINES
                        (camperFName,campLName,camperAddress,camperCity,camperZip,camperCountry,camperPhone,camperEmail,@camperAltEmail,@camperDOB,camperAge,camperSchool,camperGradYear,camperGPA,camperACT/SAT,camperPar,camperParPhone,camperPrimPos,camperSecPos);";
SET camperDOB = STR_TO_DATE(@camperDOB, '%b-%d-%Y'),
    camperAltEmail = NULLIF(@camperAltEmail, 'null');"
    // Run SQL query
    $DB->execute($SQL_statement);

CSV文件中的前两行并不重要，并且有一行是标题，这就是为什么我跳过前三行的原因。文件中的日期格式是6/5/1999，所以我假设我必须尝试更改它。我把＆＃34; LINES TERMINATED BY＆＃39; \ n＆＃39; IGNORE 3 LINES＆＃34;但我不确定我是否应该这样做，线条不会被任何东西终止。

我正在使用phpMyAdmin作为我的数据库，以防这很重要。

当我尝试执行此操作时，它只会转到一个页面，表明该页面不起作用...所以我知道我可能会离开或丢失一些东西。任何帮助将不胜感激，谢谢！

编辑：这是我的PHP文件，其中包含Vasiliy Zverev建议的更改。现在它不工作，因为显然phpMyAdmin有LOAD DATA LOCAL INFILE命令的问题？

 <?php
    // version 1.02
    // display errors for debugging
    ini_set("display_errors", true);
    error_reporting(E_ALL);

    // Open a connection to the SQL server so we can run queries later. 
    $conn = new mysqli(removed for privacy); // DON'T FORGET TO EDIT THIS PART!
    // Output error info if there was a connection problem
    if ($conn->connect_errno) {
        die("<h3> Uh oh! It looks like we're having trouble connecting to the 
 website at the moment. Try again soon! {$conn->connect_error}</h3>");
    }

    // file name
    $file_contents = $_FILES["uploadedfile"]["tmp_name"];

    $SQL_statement = "LOAD DATA LOCAL INFILE '$file_contents' INTO TABLE C_CAMPER FIELDS TERMINATED BY ','
                        LINES TERMINATED BY '\n' IGNORE 3 LINES
                        (camperFName,campLName,camperAddress,camperCity,camperZip,camperCountry,camperPhone,camperEmail,@camperAltEmail,@camperDOB,camperAge,camperSchool,camperGradYear,camperGPA,`camperACT/SAT`,camperPar,camperParPhone,camperPrimPos,camperSecPos)
                        SET camperDOB = STR_TO_DATE(@camperDOB, '%m/%d/%Y'),
                            camperAltEmail = NULLIF(@camperAltEmail, 'null');";
    // Run SQL query
    if( !$conn->query($SQL_statement)) {
        echo $conn->error;
    }

    // Close the SQL connection
    $conn->close();
?>

Answer 1

尝试

<?php
    // version 1.02
    // display errors for debugging
    ini_set("display_errors", true);
    error_reporting(E_ALL);

    // Open a connection to the SQL server so we can run queries later. 
    $conn = new mysqli(removed for privacy); // DON'T FORGET TO EDIT THIS PART!
    // Output error info if there was a connection problem
    if ($conn->connect_errno) {
        die("<h3> Uh oh! It looks like we're having trouble connecting to the 
 website at the moment. Try again soon! {$conn->connect_error}</h3>");
    }

    // file name
    $file_contents = $_FILES["uploadedfile"]["tmp_name"];

    $SQL_statement = "LOAD DATA LOCAL INFILE '$file_contents' INTO TABLE C_CAMPER FIELDS TERMINATED BY ','
                        LINES TERMINATED BY '\n' IGNORE 3 LINES
                        (camperFName,campLName,camperAddress,camperCity,camperZip,camperCountry,camperPhone,camperEmail,@camperAltEmail,@camperDOB,camperAge,camperSchool,camperGradYear,camperGPA,`camperACT/SAT`,camperPar,camperParPhone,camperPrimPos,camperSecPos)
                        SET camperDOB = STR_TO_DATE(@camperDOB, '%m/%d/%Y'),
                            camperAltEmail = NULLIF(@camperAltEmail, 'null');";
    // Run SQL query
    if( !$conn->query($SQL_statement)) {
        echo $conn->error;
    }

    // Close the SQL connection
    $conn->close();
?>

使用PHP

1 个答案: