Question

我的索引“国家/地区”有一个数据框我想更改多个国家/地区的名称，我在字典中有旧/新值，如下所示：

我尝试将列表中的值拆分为列表，但这也不起作用。代码没有错误，但我的数据框中的值没有改变。

`import pandas as pd
import numpy as np

energy = (pd.read_excel('Energy Indicators.xls', 
                        skiprows=17, 
                        skip_footer=38))

energy = (energy.drop(energy.columns[[0, 1]], axis=1))
energy.columns = ['Country', 'Energy Supply', 'Energy Supply per Capita', '% Renewable']          
energy['Energy Supply'] = energy['Energy Supply'].apply(lambda x: x*1000000)

#This code isn't working properly
energy['Country'] = energy['Country'].replace({'China, Hong Kong Special Administrative Region':'Hong Kong', 'United Kingdom of Great Britain and Northern Ireland':'United Kingdom', 'Republic of Korea':'South Korea', 'United States of America':'United States', 'Iran (Islamic Republic of)':'Iran'})`

解决：这是我没有注意到的数据的问题。

energy['Country'] = (energy['Country'].str.replace('\s*\(.*?\)\s*', '').str.replace('\d+',''))

该行位于“问题”行下，实际上需要在替换可行之前将其清理干净。例如。美利坚合众国20实际上是在excel文件中，所以替换跳过了它

感谢您的帮助!!

Answer 1

您需要通过prefixed your table and created it according to WP standards删除上标：

d = {'China, Hong Kong Special Administrative Region':'Hong Kong', 
     'United Kingdom of Great Britain and Northern Ireland':'United Kingdom', 
     'Republic of Korea':'South Korea', 'United States of America':'United States', 
     'Iran (Islamic Republic of)':'Iran'}

energy['Country'] = energy['Country'].str.replace('\d+', '').replace(d)

您还可以改进解决方案 - 使用参数usecols过滤列，使用names设置新列名称：

names = ['Country', 'Energy Supply', 'Energy Supply per Capita', '% Renewable']

energy = pd.read_excel('Energy Indicators.xls', 
                        skiprows=17, 
                        skip_footer=38,
                        usecols=range(2,6), 
                        names=names)


d = {'China, Hong Kong Special Administrative Region':'Hong Kong', 
     'United Kingdom of Great Britain and Northern Ireland':'United Kingdom', 
     'Republic of Korea':'South Korea', 'United States of America':'United States', 
     'Iran (Islamic Republic of)':'Iran'}

#for multiple is faster use *
energy['Energy Supply'] = energy['Energy Supply'] * 1000000
energy['Country'] = energy['Country'].str.replace('\d', '').replace(d)
#print (energy)

从列表

1 个答案: