Question

我只有2个查询：

查询1：

SELECT orderID, paid, orderPrice, orderDate, payDate, Orders.customerID, Customers.cusName, Customers.cusEmail, Customers.totalOrderVolume, sum(orderPrice)
FROM Orders
INNER JOIN Customers
ON Orders.customerID=Customers.customerID
WHERE paid = 1
GROUP BY customerID

QUERY2：

SELECT count(*) "numberTest"
FROM Orders
GROUP BY customerID

我在运行时将它们一起加入到1个输出表中，因此您可以看到第一个查询有10列而另外1列，如何将第二个查询中的1列添加到第一个查询中输出是一个表，其中1列添加到结尾，因此输出表在运行时有11列。

在此先感谢，我花了好几个小时试图解决这个问题，我是一名SQL初学者，我无法弄明白。

提前致谢。

Answer 1

SELECT A.orderID，A.paid，A.orderPrice，A.orderDate，A.payDate，A.customerID，A.cusName，A.cusEmail，A.totalOrderVolume，A.sum，B.numberTest 从（SELECT orderID，paid，orderPrice，orderDate，payDate，Orders.customerID as customerID，Customers.cusName，Customers.cusEmail，Customers.totalOrderVolume，sum（orderPrice）as sum FROM Orders INNER JOIN Customers ON Orders.customerID = Customers.customerID WHERE paid = 1 GROUP BY customerID）为A 内部联接（SELECT Orders.customerID as customerID，count（*）as numberTest FROM Orders GROUP BY customerID）as B ON A.customerID = B.customerID

**我认为customerID对于这两个表都是通用的。

Answer 2

SELECT A.orderID，A.paid，A.orderPrice，A.orderDate，A.payDate，A.customerID，A.cusName，A.cusEmail，A.totalOrderVolume，A.sum，B.numberTest FROM（SELECT orderID，paid，orderPrice，orderDate，payDate，Orders.customerID as customerID，Customers.cusName，Customers.cusEmail，Customers.totalOrderVolume，sum（orderPrice）as sum FROM Orders INNER JOIN Customers ON Orders.customerID = Customers.customerID WHERE paid = 1 GROUP BY customerID）作为INNER JOIN（SELECT Orders.customerID as customerID，count（*）as numberTest FROM Orders GROUP BY customerID）as B ON A.customerID = B.customerID

Answer 3

从您的问题中不清楚这两个查询的目标是什么，以及它们是如何相关的，但这可以按照您在问题中提出的方式进行。

SELECT 
    orderID,
    paid,
    orderPrice,
    orderDate,
    payDate,
    Orders.customerID,
    Customers.cusName,
    Customers.cusEmail,
    Customers.totalOrderVolume,
    sum(orderPrice),
    count(*) as `numberTest`
FROM Orders
INNER JOIN Customers
ON Orders.customerID=Customers.customerID
WHERE paid = 1
GROUP BY customerID

mySQL，我如何一起加入2个查询？

3 个答案: