Question

我将自动完成功能应用于搜索框但是当我在搜索框中键入某个值时，它总是给我相同的结果。
我意识到我没有遍历数据库，这就是为什么我一直得到相同的结果我改变了我的查询，以便我可以得到我想要的但结果仍然相同这是我自动完成的ajax，我不确定这是正确的方法吗？但是搜索功能正在工作，除了它不显示所有数据。

function autoComplete(){

        $('#keywords').autocomplete({
        source: 'autoComplete.php',
        minLength : 3,
        select: function(event, ui) {
            console.log(ui);
            $('#chosenEvent').append(ui.item.value + "\n"); 
        }
    });

这是php代码

<?php
// include the file for the database connection
include_once("database_conn_getOffers.php");

function autoC($conn){

    $sql = "select eventTitle from te_events_special_offers eventTitle ORDER BY eventTitle";

    $rsOffer = mysqli_query($conn, $sql);
    //$offer = mysqli_fetch_all($rsOffer, MYSQLI_ASSOC);

    $titles = array();

    while($title = mysqli_fetch_assoc($rsOffer)){
        $titles[] = $title;
    }
     foreach ($titles as $title)

    return json_encode($title);
}
echo autoC($conn)

?>

以下是我引用click here

的链接

感谢您的帮助！
所以现在，我使用以下代码更改了ajax方法，它可以工作，但我仍然不知道我之前的ajax代码有什么问题。我还删除了foreach并添加了implode方法

来修改php代码

$.ajax({
        method :"get",
        url :"autoComplete.php"
    })
    .done(function(data, status, jqxhr){
        var eventList;
        console.log(data);
        eventList = data.split(',');
        $("#keywords").autocomplete({
        minLength :2 ,
        source : eventList,
        select: function(event,ui){
            console.log(ui);
            }
        //end autocompoete  
        });
    });

Answer 1

请尝试首先要对结果进行编码，然后我们会使用它们。同时运行此代码，而不是其他任何，并告诉我们你得到了什么（我假设你有列ID + TITLE，如果没有，请在使用前更正代码）。此外，你原始的查询似乎很奇怪 - ＆gt; $ sql =“SELECT eventTitle FROM te_events_special_offers eventTitle ORDER BY eventTitle”; / *检查它的粗体部分* /

加号：你应该考虑预备语句和error_reporting

<?php

error_reporting(E_ALL);
ini_set('display_errors', 1);

include"config.inc.php";

$mysqli = mysqli_connect("$host", "$user", "$mdp", "$db");

if (mysqli_connect_errno()) { echo "Error connecting : " . mysqli_connect_error($mysqli); }

$query = " SELECT idTitle, eventTitle FROM te_events_special_offers ORDER BY eventTitle "; /* check names used here and adapt to yours */
$stmt = $mysqli->prepare($query);

$results = $stmt->execute();
$stmt->bind_result($idTitle, $eventTitle);
$stmt->store_result();

  if ($stmt->num_rows > 0) {
  $events = array();
  $event = array();
   while($stmt->fetch()){
    echo"[ $idTitle -> $eventTitle ]<br />";

    $event["id"] = "$idTitle";
    $event["title"] = "$eventTitle";

    array_push($events, $event);
 }
}
else
{ echo"[ no data ]"; }

print_r($events);
echo json_encode($events);

?>

Answer 2

试试这个

$sql = "select eventTitle from te_events_special_offers eventTitle ORDER BY eventTitle";

$rsOffer = mysqli_query($conn, $sql);

$titles = array();

while($title = mysqli_fetch_assoc($rsOffer)){
    $titles[] = $title;
}

return json_encode($title);

autoComplete不显示所有数据

2 个答案: