什么*重启数据从start *预取*意味着在caffe中

Question

我一直在阅读日志输出从开始重新启动数据预取。显然，这意味着一个人没有足够的数据，数据从一开始就被预取*。但是，我的数据集存在10.000个数据样本，我的批量大小为4.如何预取数据是可能的，因为我的批量大小为4，这意味着每次迭代需要4个数据样本。任何人都可以澄清我的理解吗？

LOG：

I0409 20:33:35.053406 20072 data_layer.cpp:73] Restarting data prefetching from start.
I0409 20:33:35.053447 20074 data_layer.cpp:73] Restarting data prefetching from start.
I0409 20:33:40.320605 20074 data_layer.cpp:73] Restarting data prefetching from start.
I0409 20:33:40.320598 20072 data_layer.cpp:73] Restarting data prefetching from start.
I0409 20:33:45.591019 20072 data_layer.cpp:73] Restarting data prefetching from start.
I0409 20:33:45.591047 20074 data_layer.cpp:73] Restarting data prefetching from start.
I0409 20:33:49.392580 20034 solver.cpp:398]     Test net output #0: loss = nan (* 1 = nan loss)
I0409 20:33:49.780678 20034 solver.cpp:219] Iteration 0 (-4.2039e-45 iter/s, 20.1106s/100 iters), loss = 54.0694
I0409 20:33:49.780731 20034 solver.cpp:238]     Train net output #0: loss = 54.0694 (* 1 = 54.0694 loss)
I0409 20:33:49.780750 20034 sgd_solver.cpp:105] Iteration 0, lr = 0.0001
I0409 20:34:18.812854 20034 solver.cpp:219] Iteration 100 (3.44442 iter/s, 29.0325s/100 iters), loss = 21.996
I0409 20:34:18.813213 20034 solver.cpp:238]     Train net output #0: loss = 21.996 (* 1 = 21.996 loss)

Answer 1

如果您有10,000个样品，并且您批量处理4个样品，则意味着在10,000 / 4 = 2,500次迭代后，您将处理所有数据，并且caffe将从头开始读取数据。
顺便说一句，将所有样本翻过一次也被称为＆＃34; epoch＆＃34;。

每个纪元后caffe将打印到日志

  

从开始重新启动数据预取