Question

   public function getCheckoutForm(){
   $arr = array(
        'cmd' => '_cart',
        'business' => 'some@mail',
        'no_shipping' => '1',
        'upload' => '1',
        'return' => 'url',
        'cancel_return' => 'url1',
        'no_note' => '1',
        'currency_code' => 'url2',
        'bn' => 'PP-BuyNowBF');

   $cpt=1;
   foreach($this->items as $item){
        $arr1[] = array(
            'item_number_'.$cpt.'' => $item['item_id'],
            'item_name_'.$cpt.'' => $item['item_name'],
            'quantity_'.$cpt.'' => $item['item_q'],
            'amount_'.$cpt.'' => $item['item_price']
            );
        $cpt++;
   }
    return array_merge($arr,$arr1[0],$arr1[1]);
}

这会返回如下数组：

    Array
(
    [cmd] => _cart
    [business] => some@mail
    [no_shipping] => 1
    [upload] => 1
    [return] => url1
    [cancel_return] =>url2
    [no_note] => 1
    [currency_code] => EUR
    [bn] => PP-BuyNowBF
    [item_number_1] => 28
    [item_name_1] => item_name_1
    [quantity_1] => 1
    [amount_1] => 5
    [item_number_2] => 27
    [item_name_2] => item_name_2
    [quantity_2] => 1
    [amount_2] => 30
)

问题是返回$ arr1 [0]和$ arr1 [1]是硬编码的。如果在循环中我有超过2个数组，让我们说0,1,2,3 ans等等，这段代码将无效。任何的想法？也许我的逻辑是完全错误的......

Answer 1

我可能会做类似

的事情

$count = count($arr1);
for($i=0;$i<$count;$i++){
     $arr = array_merge($arr,$arr1[$i]);
}
return $arr;

Answer 2

我希望，我明白，你的意思^^

foreach ($i = 0, $n = count($arr1); $i < $n; $i++) {
  $arr = array_merge($arr, $arr1[$i]);
}
return $arr;

Answer 3

您可以在每次迭代中进行合并：

foreach($this->items as $item){
    $temp_arr = array(
        'item_number_'.$cpt.'' => $item['item_id'],
        'item_name_'.$cpt.'' => $item['item_name'],
        'quantity_'.$cpt.'' => $item['item_q'],
        'amount_'.$cpt.'' => $item['item_price']
    );
    $arr = array_merge($arr,$temp_arr)
    $cpt++;
}

，其优势在于您可以从函数中获取$temp_arr，

或者只是将所有元素添加到一个数组中：

foreach($this->items as $item){
    $arr['item_number_'.$cpt.''] => $item['item_id'];
    $arr['item_name_'.$cpt.''] => $item['item_name'];
    $arr['quantity_'.$cpt.''] => $item['item_q'];
    $arr['amount_'.$cpt.''] => $item['item_price'];
    $cpt++;
}

Answer 4

这样做

$count = count($data);
    $sum = 1;
    $arr = [];
    for($i=0;$i<$count;$i++){
        $temp = $arr;
        if($i == $count - 1){
            $sum = 0;
        }
        $arr = array_merge($temp,$data[$i + $sum]);
    }
    return $arr;

PHP：循环合并数组

5 个答案: