Question

（目前在Xcode 8.2和swift3上）

一旦我更新到swift3，我就会出现此错误

＆＃34;由于信号命令失败：分段错误：11＆＃34;

因为我有大量keys＆amp;单个字典中的values。

当我挖掘出来时，我发现字典的键和值有限，当我添加超过特定数量的键时值，上面的错误显示出来。

解决此错误的最佳方法是什么？

如何使字典容纳更多的键和值？

import Foundation

open class TranslateDictionary {

    var translateDictionary: [String: String] = [

        "alphabetic": "one",
        "categories": "two",
        "levels": "three",
        "mlevel1": "four",
        "mlevel2": "five",
        "mlevel3": "six",
        "mlevel4": "seven",
        "mlevel5": "eight",
        "mlevel6": "nine",

               //It contain a lot of keys and values not just those above!
]



    func toArabic(_ label: String) -> String {
        var arabic = translateDictionary[label]

        if (arabic == nil) {
            arabic = "NoTranslation"
        }

        return arabic!
    }
}

Answer 1

尝试插入这样的键：

var translateDictionary: [String: String] = {
    var translateDictionary = [String: String]()
    translateDictionary["key1"] = "value1"
    translateDictionary["key2"] = "value2"
    ...
    return translateDictionary
}()

您可能正在为字典文字命中大小限制。

顺便说一句，你的toArabic函数会看起来像 Swifty 这样;＃）

func toArabic(_ label: String) -> String {
    guard let arabic = translateDictionary[label] else {
        return "NoTranslation"
    }
    return arabic
}

swift3字典限制命令由于信号而失败：分段错误：11

1 个答案: