添加新子项时dispatch_group_leave错误

时间:2017-04-09 07:13:01

标签: ios swift firebase swift3 firebase-realtime-database

我正在尝试使用以下代码将新子项添加到firebase中的节点:

@IBAction func likeButtonOnTouch(_ sender: Any) {

    if ViewController.usersUid.count > 0 {

        self.update()

    }
}

func update() {
    let child1: String = (FIRAuth.auth()?.currentUser?.uid)!
    let ref = FIRDatabase.database().reference().child(child1).child("following")


    let data1: [String:String] = [ViewController.usersUid[self.currentUser]: "true"]

    ref.setValue(data1)
}

但是当我按下按钮时,我的应用程序因此错误而崩溃:

  

线程1 exc_bad_instruction(code = 1 subcode = 0x100ef5c78)

在这一行:

ref.setValue(data1)

我不知道这意味着什么,以及如何解决它。该值已成功添加到我的数据库(!!!)最有趣的事情,但应用程序崩溃。请给我一个建议。

P.S。崩溃报告:

* thread #1: tid = 0xb503, 0x0000000100f11c78 libdispatch.dylib`dispatch_group_leave + 76, queue = 'com.apple.main-thread', stop reason = EXC_BREAKPOINT (code=1, subcode=0x100f11c78)
frame #0: 0x0000000100f11c78 libdispatch.dylib`dispatch_group_leave + 76
frame #1: 0x00000001000a36f8 Elite Club`thunk + 68 at ViewController.swift:0
frame #2: 0x00000001001bf8a4 Elite Club`__43-[FValueEventRegistration fireEvent:queue:]_block_invoke.57((null)=<unavailable>) + 88 at FValueEventRegistration.m:60 [opt]
frame #3: 0x0000000100f0d258 libdispatch.dylib`_dispatch_call_block_and_release + 24
frame #4: 0x0000000100f0d218 libdispatch.dylib`_dispatch_client_callout + 16
frame #5: 0x0000000100f12280 libdispatch.dylib`_dispatch_main_queue_callback_4CF + 1200
frame #6: 0x000000019376e810 CoreFoundation`__CFRUNLOOP_IS_SERVICING_THE_MAIN_DISPATCH_QUEUE__ + 12
frame #7: 0x000000019376c3fc CoreFoundation`__CFRunLoopRun + 1660
frame #8: 0x000000019369a2b8 CoreFoundation`CFRunLoopRunSpecific + 444
frame #9: 0x000000019514e198 GraphicsServices`GSEventRunModal + 180
frame #10: 0x00000001996e17fc UIKit`-[UIApplication _run] + 684
frame #11: 0x00000001996dc534 UIKit`UIApplicationMain + 208
frame #12: 0x00000001000c04b8 Elite Club`main + 140 at AppDelegate.swift:15
frame #13: 0x000000019267d5b8 libdyld.dylib`start + 4

2 个答案:

答案 0 :(得分:1)

如果ViewController.usersUid[self.currentUser]不存在请崩溃

你能尝试这种方式:

let data1: [String:String] = [(ViewController.usersUid[self.currentUser] ?? "") : "true"]

ref.setValue(data1) { (error, ref) -> Void in

}

更清洁的方式:

if let currentuser =  ViewController.usersUid[self.currentUser]  {

    let data1: [String:String] = [currentuser : "true"]

    ref.setValue(data1) { (error, ref) -> Void in

    }

}

答案 1 :(得分:0)

经过一天的工作,我已经想通了。首先,您应该退出,然后再登录一次。这是我的最终代码:

func update() {

        do {
            let ref = try FIRAuth.auth()?.signOut()
        }
        catch {}

        let preferences = UserDefaults.standard
        FIRAuth.auth()?.signIn(withEmail: preferences.object(forKey: "userName") as! String, password: preferences.object(forKey: "userPassword") as! String) { (user, error) in

            if error == nil {
                LoggingIn.userUID = (user?.uid)!

                print(user?.uid ?? "not found")
                print("You have successfully logged in")

                let child1: String = (FIRAuth.auth()?.currentUser?.uid)!
                let ref = FIRDatabase.database().reference().child(child1).child("following")


                let data1: [String:String] = [ViewController.usersUid[self.currentUser] : "true"]



                ref.setValue(data1) { (error, ref) -> Void in

                }

            } else {


            }
        }
    }