我有多个具有相同名称的选择框。现在,当我从第一个选择框中选择值时,它将提交该值并更新数据库。当我在另一个选择框中选择和项目时,它从第一个框中提交值。我觉得javascript不对。知道什么是错的吗?
继承人我的HTML:
<video width="320" height="240" controls>
<source src="video.aspx" type="video/mp4">
Your browser does not support the video tag.
</video>
jquery的:
<?php foreach ($result as $row): ?>
<select class="form-control" name="category[]" required>
<option value="" disabled selected>Select The Category </option>
<option value="station">Station</option>
<option value="equipment">Tools/Equipment</option>
<option value="supplies">Supplies</option>
</select>
<input id="taskID" value="<?php echo $row['id']; ?>" hidden></input>
<?php endforeach; ?>
addressBook.php
$(document).on('change', 'select[name="category[]"]', function(event){
$('select[name="category[]"]').each(function(){
var formData = {
'task': $('select[name="category[]"]').val(),
'name': $('input[name="taskID[]"]').val(),
};
$.ajax({
type: 'POST',
url: 'php/addressBook.php',
data: formData,
dataType: 'html',
encode: true
})
.done(function(msg) {
$(".alert").html(msg);
})
.fail(function(data) {
console.log(data);
})
event.preventDefault();
});
});
答案 0 :(得分:2)
将类属性更改为:class="form-control categorySelect"
$('.categorySelect').change(function(event){
for(selectInstance of $('.categorySelect')){
var formData = {
'task': $(selectInstance).val(),
'name': $(selectInstance).next().val()
};
$.ajax({
type: 'POST',
url: 'php/addressBook.php',
data: formData,
dataType: 'html',
encode: true
})
.done(function(msg) {
$(".alert").html(msg);
})
.fail(function(data) {
console.log(data);
})
event.preventDefault();
}
});