现在,我正在做:
$posts = get_posts(array('post_type' => 'page', 'post__in' => array(1, 3, 2, 9, 7)));
我遇到两个问题:
'post_type' => 'post'
,所以它没有被选中,但我想要它!如果我遗漏'post_type' => 'page'
,则只选择帖子3(因为它必须假设'post_type'=>'post'。)。我希望能够order the posts arbitrarily by their ids。如果我知道如何使用MySQL,我可以这样做:
SELECT * FROM wp_posts WHERE ID IN (1, 3, 2, 9, 7)
ORDER BY FIND_IN_SET(ID, '1,3,2,9,7');
但是,我应该如何使用WordPress?
答案 0 :(得分:1)
首先通过他们的ID任意获取所有帖子,然后遍历所有帖子
你可以这样做: -
$posts=$wpdb->get_results("SELECT ID FROM $wpdb->posts WHERE ID IN (1, 3, 2, 9, 7)
ORDER BY FIND_IN_SET(ID, '1,3,2,9,7')");
$count=count($posts);
for ($counter=0 ; $counter < $count; $counter++)
{
$post=get_post( $posts[$counter]->ID, $output );
//do your stuffs with posts
}
希望这有帮助
答案 1 :(得分:0)
#wordpress IRC频道上的Kawauso告诉我“post_type需要一系列值。”从那以后,我发现以下内容也选择了帖子3:
所以,我做了以下事情:
$post_ids = array(1 => 0, 3 => 1, 2 => 2, 9 => 3, 7 => 4);
$posts = get_posts(array('post_type' => array('post', 'page'),
'post__in' => array_keys($post_ids)));
$ordered_posts = array(0,0,0,0,0); // size of five; keeps order
foreach ($posts as $p) {
setup_postdata($p);
$ordered_posts[$post_ids[$p->ID]] = array(
'permalink' => get_permalink($p->ID),
'title' => $p->post_title,
'excerpt' => get_the_excerpt(),
'date' => date('F j, Y', strtotime($p->post_date)));
}
答案 2 :(得分:0)
根据this thread,您可以使用此代码,然后使用经典的WordPress循环:
$args = array(
'post_type'=>'page',
'orderby'=>'menu_order',
'order'=>'ASC'
);
query_posts($args);