Question

我想破译一句话。对于找到的每个单词，我想在计数器中添加一个单词。我有一个嵌套的for循环，当用户输入句子时，一个for循环将循环通过句子（int i = 0）而另一个（int j = 0）将遍历数组并且当他们找到相应的字母。我认为我所做的事情会有意义，但由于某种原因，它不起作用。这是我的代码的一部分，用于处理此部分。提前谢谢你:)

#include <iostream>
#include <string>
#include <cctype>

using namespace std;
string alphebet[26] = {"A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"};

string sentence;
cin >> sentence;
for(int i = 0; i < sentence.length(); i++){
    for(int j = 0; j < alphebet; j++){
        if (sentence[i] == alphebet[j]){
            counter_letters = counter_letters + 1;
        }
    }
}

Answer 1

首先将您的alphebet更改为类似char alphabet[26]的字符数组。然后你需要使用getline(cin, sentence)来获得像'Hello World'这样的整行输入，而cin << sentence只获得第一个单词。接下来，您需要将字符串转换为大写，以便以后与alphebet匹配，并使用transform(sentence.begin(), sentence.end(), sentence.begin(), ::toupper);执行此操作。之后，请务必初始化变量counter_letters。作为旁注，您不需要执行counter_letters = counter_letters + 1;即可counter_letters += 1;或counter_letters++;或++counter_letters;。

#include <iostream>
#include <string>
#include <cctype>
#include <algorithm>

using namespace std;
int main() {
    char alphebet[26] = {'A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z'};

    string sentence;
    getline(cin,sentence);
    transform(sentence.begin(), sentence.end(), sentence.begin(), ::toupper);

    int counter_letters = 0;
    for(int i = 0; i < sentence.length(); i++){
        for(int j = 0; j < 26; j++){
            if (sentence[i] == alphebet[j]){
                counter_letters++;
            }
        }
    }
    cout << counter_letters << endl;
}

Answer 2

我不确定你的问题，但有一个主张是你可能会在输入中输入空格。 cin不读取空格，因此您的代码可能无法正常工作

如果这不是问题，请参阅下面的链接来计算字符串中的大写，小写字母 How to code a C++ program which counts the number of uppercase letters, lowercase letters and integers in an inputted string?

如何使用数组C ++从字符串中查找字母

2 个答案: