{
"DIV_1" : {
"ACTINACT" : 1,
"COORDINATOR" : "10CA056",
"DIV_CODE" : "BSL",
"DIV_ID" : 1,
"DIV_NAME" : "Bhusawal",
"ERP_LOC_CODE" : "CRB",
"MTIME" : "2017-04-08T11:02:59",
"ZONE_ID" : "ZONE_1"
},
"DIV_10" : {
"ACTINACT" : 1,
"COORDINATOR" : "06CS011",
"DIV_CODE" : "UMB",
"DIV_ID" : 10,
"DIV_NAME" : "Ambala",
"ERP_LOC_CODE" : "NRA",
"MTIME" : "2017-04-08T11:02:59",
"ZONE_ID" : "ZONE_3"
}
}
如何获得DIV_ID? 最初我需要比较密钥(Ex :: Here DIV_10)然后DIV_NAME需要得到。 提前谢谢......
答案 0 :(得分:5)
我假设DIV_1和DIV_10的父级是root。如果您的DIV_ID
值为“1”或“10”且需要获得DIV_NAME
的值,那么您应该这样做:
int divId = 1; // sample
FirebaseDatabase.getInstance().getReference().orderByChild("DIV_ID").equalTo(divId)
.addValueEventListener(new ValueEventListener() {
... onDataChange(DataSnapshot dataSnapshot) {
for (DataSnapshot snapshot : dataSnapshot.getChildren()) {
String divName = snapshot.child("DIV_NAME").getValue(String.class);
// there you go
// and please check if you have more than 1 value as result
}
}
...
}
但是如果你有像DIV_1
或DIV_10
这样的关键值,那么它应该会容易得多。像这样:
String key = "DIV_1";
FirebaseDatabase.getInstance().getReference(key)
.addValueEventListener(new ValueEventListener() {
... onDataChange(DataSnapshot dataSnapshot) {
String divName = snapshot.child("DIV_NAME").getValue(String.class);
// note that in this sample, it doesn't need to loop, because:
// data you get here is one level deeper than data you got on first sample
}
...
}
希望这有帮助