mySQL在循环代码时不起作用它总是回显“它失败了”？

Question

当我运行代码时，它只显示声明失败的回声，我认为没有丢失的括号或引号

<?php

$link = mysqli_connect("localhost", "id1242269_sql", "pass", "id1242269_sql");
if (mysqli_connect_error()) {
     die("Could not connect to database");
} 

$query = "SELECT * FROM users";
if ($result=mysqli_query($link, $query)) {
    while ($row = mysqli_fetch_array($result)) {
        print_r($row);
    }
} else {
    echo "it failed";
}
?>

Answer 1

这是mysqli_error()派上用场的地方。

if ($result=mysqli_query($link, $query)) {
    while ($row = mysqli_fetch_array($result)) {
        print_r($row);
    }
} else {
    printf("Errormessage: %s\n", mysqli_error($link)); // Print error message
}

Answer 2

$link = mysqli_connect("localhost", "id1242269_sql", "pass", "id1242269_sql");

我是新手，但在我的作业中我们使用了＆＃34; new＆＃34;在那里：

$link = new mysqli_connect("localhost", "id1242269_sql", "pass", "id1242269_sql");

Answer 3

问题在于：

$link = mysqli_connect("localhost", "id1242269_sql", "pass", "id1242269_sql");

对我来说工作得很好：

$link = mysqli_connect("localhost", "root", "", "testDb");

我的结果：