Question

我试图创建一个拼字游戏功能，它接受一串字母并根据字母返回分数。到目前为止，这是我的代码：

def scrabble_score(rack):
    count = 0
    for letter in rack:
        if letter == "EAIONRTLSU":
            count += 1
            return count
        elif letter == "DG":
            count += 2
            return count
        elif letter == "BCMP":
            count += 3
            return count        
        elif letter == "FHVWY":
            count += 4
            return count
        elif letter == "K":
            count += 5
            return count
        elif letter == "JX":
            count += 8
            return count
        else:
            letter == "QZ"
            count += 10
            return count

然而，当我试图调用该函数时

    scrabble_score("AABBWOL")

当它应该返回14时返回10？

Answer 1

代码有两个问题：

return语句应该只调用一次， for迭代结束后，所以它可以汇总所有字母值
每个if语句应检查字母是字符串，而不是等于具有特定值的字母列表。

然后它看起来像：

def scrabble_score(rack):
    count = 0
    for letter in rack:
        print letter
        if letter in "EAIONRTLSU":
            count += 1
        elif letter in "DG":
            count += 2
        elif letter in "BCMP":
            count += 3
        elif letter in "FHVWY":
            count += 4
        elif letter in "K":
            count += 5
        elif letter in "JX":
            count += 8
        else:
            count += 10
    return count

返回：14

创建python拼字游戏功能

1 个答案: