Question

我能在PHP中做点什么吗？：

for($i=0; $i <= 5; $i++){
    $anyway = $_POST['smth'].$i;
}

如何在Mysql插入函数中使用它。

$sql = "INSERT INTO try (column_1) VALUES ('".$anyway."')";

Answer 1

首先，我建议在变量中使用$ _POST ['smth']，然后再在for循环中使用它。

$smth = $_POST['smth']; //remember to sanitize strings taken from user input
$anyway = ""; // Declare $anyway before the for loop to avoid overwriting it
for($i=0; $i <= 5; $i++){
    $anyway = $smth.$i;
}

然后，您需要设置并测试数据库连接：

$mysqli = new mysqli("example.com", "user", "password", "database");
if ($mysqli->connect_errno) {
    echo "Failed to connect to MySQL: (" . $mysqli->connect_errno . ") " . $mysqli->connect_error;
}

最后，准备，绑定并执行您的查询：

$stmt = $mysqli->prepare("INSERT INTO (column_1) VALUES (?)");
$stmt->bind_param("s", $anyway);
if (!$stmt->execute()) {
    echo "Execute failed: (" . $stmt->errno . ") " . $stmt->error;
}

Php，$ _POST方法使用类似变量

1 个答案: