Question

我正在尝试创建一个随机双数组矩阵。矩阵必须是n x n的大小，并且所有数字必须在1到100之间。我一直在努力将它排序多年，我知道它必须是如此简单的东西（通常是这样）。

这是我的代码：

public static void main(String[] args) { 
    PrintRandomGraph(RandomArray(4));
}

private static double[] RandomArray(int n) {  
    double[] randomArray = new double[n];
    double[][] randomMatrix = new double [n][n];

    Random rand = new Random(); 
    rand.setSeed(System.currentTimeMillis()); 
    for (int i = 0; i < n; i++) {

        Integer r = rand.nextInt()% 100; 
        randomArray[i] = Math.abs(r);
        for (int j = 0; j < n; j++) {
            Arrays.fill(randomMatrix, i, i+1, randomArray);
        }  
    }

    return randomArray;  
}

private static void PrintRandomGraph(double[] inputArray) {
    int n = inputArray.length;
    double[] showArray = new double[n];
    double[][] showMatrix = new double [n][n];

    for (int j = 0; j < n; j++) {
        for (int i = 0; i < n; i++) {
            double r = inputArray[i];
            showArray[i] = r; 
            Arrays.fill(showMatrix, i, i+1, showArray);
        }
    }

    System.out.println(Arrays.deepToString(showMatrix));
}

当我运行代码时，我得到一个随机数组重复n次，如：

[[63.0,97.0,64.0,75.0]，[63.0,97.0,64.0,75.0]，[63.0,97.0,64.0,75.0]，[63.0,97.0,64.0,75.0]]

我想我需要回到for循环的顶部并添加新数组......？请帮忙=（

非常感谢任何帮助。谢谢。

Answer 1

你有没有试过这样的事情：

private static double[][] RandomArray(int n) {
    double[][] randomMatrix = new double [n][n];

    Random rand = new Random(); 
    rand.setSeed(System.currentTimeMillis()); 
    for (int i = 0; i < n; i++) {     
        for (int j = 0; j < n; j++) {
            Integer r = rand.nextInt()% 100; 
            randomMatrix[i][j] = Math.abs(r);
        }

    }

    return randomMatrix;
}

打印图表：

public void printGraph(double[][] array, int n) {
    for (int i = 0; i < n; i++) {     
        for (int j = 0; j < n; j++) {
            System.out.println(array[i][j]);
        } 
    }
}

使用方括号打印图表：

public void printGraph(double[][] array, int n) {
        for (int i = 0; i < n; i++) {  
            System.out.print(" [ ");   
            for (int j = 0; j < n; j++) {
                System.out.print(array[i][j]);
            } 
            //Put println instead of print here to have each row in a new line
            System.out.print(" ]");
        }
    }

另外，这看起来很像家庭作业，如果是的话，请像这样标记：）

Answer 2

大家都提供了我正在寻找的答案

 private static double[][] RandomArray(int n) {
        double[][] randomMatrix = new double [n][n];
        double[] randomArray = new double [n];
         Random rand = new Random(); 
            rand.setSeed(System.currentTimeMillis()); 

        for (int i = 0; i < n; i++) {   

            for (int j = 0; j < n; j++) {
                Integer r = rand.nextInt()% 100; 
                randomMatrix[i][j] = Math.abs(r);
            }

        }

        return randomMatrix;
    }


public static void main(String[] args){

        //PrintRandomGraph(RandomArray(5));
    System.out.println(Arrays.deepToString(RandomArray(5)));
}

如何在Java中显示N×N随机数矩阵？

2 个答案: