import sqlite3
db = sqlite3.connect('newdb.db')
team_list = ['Munster', 'Leinster', 'Ulster', 'Glasgow']
cursor = db.cursor()
for i in range(len(team_list)):
team_names = team_list[i].upper()
searchStr = '%' + team_names + '%'
cursor.execute('select * from tickets where Name LIKE ?', (searchStr,))
teams_points = cursor.fetchall()
print teams_points
cursor.close()
db.close()
这是我的python代码,用于显示表格中的所有数据'在newdb.db中。我有一个包含团队名称的列表,我希望能够在数据库中搜索这些团队名称并计算出售门票的信息。 picture of database
[(u'MUNSTER', 5, u'First Round'), (u'MUNSTER', 5, u'First Round'),
(u'MUNSTER', 8, u'Second Round'), (u'MUNSTER', 10, u'Both Rounds')]
[(u'LEINSTER', 2, u'Second Round'), (u'LEINSTER', 16, u'First Round'),
(u'LEINSTER', 5, u'Both Rounds'), (u'LEINSTER', 6, u'Both Rounds'),
(u'LEINSTER', 3, u'First Round')]
[(u'ULSTER', 10, u'Second Round')]
[(u'GLASGOW', 4, u'First Round')]
当我运行脚本时,上面是我的输出,我希望能够将每个团队放入列表中
team_list=['team_name', 'total first round tickets', 'second round tickets']
munster_list = ['MUNSTER', '20', '18']
leinster_list = ['LEINSTER','30','13']
ulster_list = ['ULSTER','0','10']
glasgow_list = ['GLASGOW','4','0']
然后打印列表我可以使用print munster_list
答案 0 :(得分:0)
使用GROUP BY从每个组的行中获取一个输出行。使用CASE expressions仅汇总某些值:
SELECT Name,
sum(CASE WHEN Type IN ('First Round', 'Both Rounds')
THEN Amount
ELSE 0
END) AS "first round tickets",
sum(CASE WHEN Type IN ('Second Round', 'Both Rounds')
THEN Amount
ELSE 0
END) AS "second round tickets"
FROM tickets
GROUP BY Name
ORDER BY Name;