Question

jQuery代码：

$("#ProjectType").change(function(){
    alert($("#ProjectType").val());
    if($("#ProjectType").val() == '16' || $("#ProjectType").val() == '17' || $("#ProjectType").val() == '18' || $("#ProjectType").val() == '19' || $("#ProjectType").val() == '20' ||response $("#ProjectType").val() == '21' || $("#ProjectType").val() == '22' || $("#ProjectType").val() == '23' || $("#ProjectType").val() == '24' || $("#ProjectType").val() == '25' || $("#ProjectType").val() == '26' || $("#ProjectType").val() == '27'){
        $("#BHKshow").hide();
        alert('if');
    }
    else{
        $("#BHKshow").show();
    }
})

它在控制台中显示unexpected identifier错误。如何解决此错误？

Answer 1

试试这个：

$("#ProjectType").change(function(){
    var projectValue = $("#ProjectType").val();
    alert(projectValue);
    if(projectValue == '16' || projectValue == '17' || projectValue == '18' || projectValue == '19' || projectValue == '20' || projectValue == '21' || projectValue == '22' || projectValue == '23' || projectValue == '24' || projectValue == '25' || projectValue == '26' || projectValue == '27'){
        $("#BHKshow").hide();
        alert('if');
    }
    else{
        $("#BHKshow").show();
    }
});

jQuery意外标识符错误

1 个答案: