Question

美好的一天！[/ p>

我有这个代码块，我创建了一个JSON字符串，我有一个动态数据，所以我需要的也是一个密钥的动态名称..

if (mysql_num_rows($result) > 0) {
    $response["members"] = array();
    $x = 0;
    $members = array();
    while ($row = mysql_fetch_array($result)) {
        $members = array();
        $members["member" + (string)$x] = array();
        $member["member_id"] = $row["member_id"];
        $member["firstname"] = $row["firstname"];
        $member["mi"] = $row["mi"];
        $member["lastname"] = $row["lastname"];
        $member["email"] = $row["email"];
        $member["username"] = $row["username"];
        $member["password"] = $row["password"];
        $member["guild_id"] = $row["guild_id"];
        $member["guild_name"] = $row["guild_name"];
        $member["guild_code"] = $row["guild_code"];
        array_push($members["member" + (string)$x], $member);
        $x++;
    }
    array_push($response["members"], $members);

    echo json_encode($response);;
}

在JQuery中这种方法有效..我的问题是，有什么方法可以用php实现它吗？如果你知道我会很高兴知道...

Answer 1

如果您想要实现members数组包含密钥为member0，member1等的单个记录，那么您可以继续：

if (mysql_num_rows($result) > 0) {
    $x = 0;
    $members = array();
    while ($row = mysql_fetch_array($result)) {
        $member = array();
        $member["member_id"] = $row["member_id"];
        $member["firstname"] = $row["firstname"];
        $member["mi"] = $row["mi"];
        $member["lastname"] = $row["lastname"];
        $member["email"] = $row["email"];
        $member["username"] = $row["username"];
        $member["password"] = $row["password"];
        $member["guild_id"] = $row["guild_id"];
        $member["guild_name"] = $row["guild_name"];
        $member["guild_code"] = $row["guild_code"];
        $members["member$x"] = $member;
        $x++;
    }
    $response["members"] = $members;

    echo json_encode($response);
}

Answer 2

1.Suggestion：-stop使用已弃用+删除（php5 + php7）版本的mysql_*。移向mysqli_* OR PDO以及prepared statements（防止Sql注入））

2.为什么要创建不必要的数组和多次推送。不需要这样做。如下所示： -

$response["members"] = array();//put outside
if (mysql_num_rows($result) > 0) {
    $x = 0;
    while ($row = mysql_fetch_array($result)) {
        $response["members"][$x]["member_id"] = $row["member_id"]; //assign value directly to the resultant array
        $response["members"][$x]["firstname"] = $row["firstname"];
        $response["members"][$x]["mi"] = $row["mi"];
        $response["members"][$x]["lastname"] = $row["lastname"];
        $response["members"][$x]["email"] = $row["email"];
        $response["members"][$x]["username"] = $row["username"];
        $response["members"][$x]["password"] = $row["password"];
        $response["members"][$x]["guild_id"] = $row["guild_id"];
        $response["members"][$x]["guild_name"] = $row["guild_name"];
        $response["members"][$x]["guild_code"] = $row["guild_code"];
        $x++;
    }
}

if(count($response["members"])>0){ //check finally that array is not empty
 echo json_encode($response); //echo json encoded array data
}

PHP数组字符串键末尾添加数字

2 个答案: