Question

我有一张这样的表：

Store_Id | Week 
---------+--------
   A1    | 201601
   A1    | 201602
   A1    | 201604
   A1    | 201606
   A1    | 201607
   A2    | 201552
   A2    | 201603
   A2    | 201604
   A2    | 201605
   A2    | 201608

我需要在此旁边派生一个动态周列，理想情况下如下：

Store_Id | Week   | Dynamic_Week
---------+--------+-------------
   A1    | 201602 |    1
   A1    | 201603 |    2
   A1    | 201605 |    4
   A1    | 201606 |    5
   A1    | 201607 |    6
   A2    | 201552 |    1
   A2    | 201603 |    4
   A2    | 201604 |    5
   A2    | 201605 |    6
   A2    | 201608 |    9

逻辑是：每个商店的MIN（周）被视为相应商店的第一周销售。动态周中的先前值将根据每个商店的第一周销售额的参考值递增。

我尝试了Row_Number()，RANK()，DENSE_RANK()，但无法获得所需的解决方案。所有这三件事都没有用。

任何人都可以向我提出可能的解决方案。

提前致谢。

Answer 1

select a.storeID,a.week,b.min_week,(a.week-b.min_week+1) as Dynamic_week
from
table1 as a 
join
(select distinct storeId,min(week) as min_week from table1 group by 1) as b
where a.store_id=b.store_id

我不确定这会对sql-server有效，我不习惯使用sql-server使这段代码与sql-server兼容

Answer 2

编辑：使查询动态化以处理任何年份，而不仅仅是1年。

New Restester Sample 的

+----------+--------+--------------+
| Store_Id |  Week  | dynamic_week |
+----------+--------+--------------+
| A1       | 201602 |            1 |
| A1       | 201607 |            6 |
| A2       | 201552 |            1 |
| A2       | 201603 |            4 |
| A2       | 201704 |           57 |
| A3       | 201352 |            1 |
| A3       | 201601 |          106 |
+----------+--------+--------------+

更复杂样本的输出

SELECT t1.*,
       CASE
           WHEN (t1.week-t.week1+1)>=52 
           THEN (t1.week-t.week1+1)-48
           ELSE (t1.week-t.week1+1)
       END AS dynamic_week
FROM table1 t1
INNER JOIN
  (SELECT store_id,
          min(week) AS week1
   FROM table1
   GROUP BY store_id) t 
ON t1.store_id=t.store_id

上一个：这就是你需要的。虽然您的样本数据和预期数据不匹配，此解决方案仅适用于跨越1年的store_id。不仅如此，您还需要稍微更改一下查询。但这对你的样本有好处。

Restester Sample 的

+----------+--------+--------------+
| Store_Id |  Week  | dynamic_week |
+----------+--------+--------------+
| A1       | 201602 |            1 |
| A1       | 201604 |            3 |
| A1       | 201606 |            5 |
| A1       | 201607 |            6 |
| A2       | 201552 |            1 |
| A2       | 201603 |            4 |
| A2       | 201604 |            5 |
| A2       | 201605 |            6 |
| A2       | 201608 |            9 |
+----------+--------+--------------+

我的样本输出

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在SQL中派生动态列

2 个答案: