Question

我有一个Jenkinsfile，我想从shell脚本中读取一些值。

该文件的部分是

-- Jenkinsfile
stage ('Setup Vars') {
  switch(BRANCH_NAME) {
    case 'develop':
      env.ECHO_CHAMBER_BRANCH = 'develop'
      env.HENDRICKS_JS_INTEGRATION_BRANCH = 'master'
      env.FEATURES_BRANCH = 'master'
    break
    case 'master':
      env.ECHO_CHAMBER_BRANCH = 'develop'
      env.HENDRICKS_JS_INTEGRATION_BRANCH = 'master'
      env.FEATURES_BRANCH = 'master'
    break
    default:
      env.ECHO_CHAMBER_BRANCH = 'feature-branch'
      env.HENDRICKS_JS_INTEGRATION_BRANCH = 'feature-branch'
      env.FEATURES_BRANCH = 'feature-branch'
    break
  }
}

我需要在case语句的默认部分中读取分配给env.ECHO_CHAMBER_BRANCH，env.HENDRICKS_JS_INTEGRATION和env.FEATURES_BRANCH的值，因此在此示例中我希望feature-branch返回对于每个变量。

使用shell脚本，我该如何获取这些值？

Answer 1

改进了Signal脚本（用法“ case_to_var filename ”）：

case_to_var

#!/bin/sed -nf # Only look at lines ending in ':' /:$/{ # remove leading `case`, spaces, and the ':', and save name. s/.* \|://g h # until the `break` line, recall name, append variable name, # and make it shell-parsable. :foo g N y/./_/ s/'//g s/ = /=/ s/\n.*env//gp /break$/!b foo }的输出：

case_to_var Jenkinsfile

使输出shell可解析，允许执行和使用它;与谨慎使用develop_ECHO_CHAMBER_BRANCH=develop develop_HENDRICKS_JS_INTEGRATION_BRANCH=master develop_FEATURES_BRANCH=master master_ECHO_CHAMBER_BRANCH=develop master_HENDRICKS_JS_INTEGRATION_BRANCH=master master_FEATURES_BRANCH=master default_ECHO_CHAMBER_BRANCH=feature-branch default_HENDRICKS_JS_INTEGRATION_BRANCH=feature-branch default_FEATURES_BRANCH=feature-branch：

一样

eval

输出：

eval $(case_to_var Jenkinsfile)
echo $default_FEATURES_BRANCH $develop_FEATURES_BRANCH

单线版：

feature-branch master

使用shell脚本从文件读取值

1 个答案: