我在C中读取/写入二进制文件时遇到错误。问题是: - 我使用fwrite将int(例如2)写入文件 - 我尝试使用fread从文件中读取此int - 当我读它时,它不是2,而是一些长数,例如967899906或2071332354或1030372866(总是不同)。
我在C中写入二进制文件,如下所示:
letter = letter || Char.IsLetter(character);
然后我从文件中读到这样的内容:
FILE * writeFile = fopen("test.bin","wb");
//test int vars
int test1 = 1;
int test2 = 2;
int test3 = 3;
//writing some ints to binary file
fwrite(&test1,1,1, writeFile);
fwrite(&test2,1,1, writeFile);
fwrite(&test3,1,1, writeFile);
fclose(writeFile);
答案 0 :(得分:0)
fwrite希望第二个参数是要写入的数据大小,因此在您的情况下sizeof(int)
fread
#include <stdio.h>
int main(void)
{
FILE * writeFile = fopen("test.bin","wb");
if (writeFile != NULL)
{
//test int vars
int test1 = 1;
int test2 = 2;
int test3 = 3;
//writing some ints to binary file
fwrite(&test1,sizeof(test1),1, writeFile);
fwrite(&test2,sizeof(test2),1, writeFile);
fwrite(&test3,sizeof(test3),1, writeFile);
fclose(writeFile);
}
else
{
perror("Error opening file to write: ");
return 1;
}
FILE *readFile = fopen("test.bin","rb");
if (readFile != NULL)
{
int data;
while(fread(&data,sizeof(data),1, readFile)==1){
printf("%d\n", data);
}
fclose(readFile);
}
else
{
perror("Error opening file to read: ");
return 1;
}
return 0;
}
提示:始终测试fopen
是否成功。
修改强>
要使用1字节变量(如注释),只需使用uint8_t
变量
#include <stdio.h>
#include <stdint.h>
int main(void)
{
FILE * writeFile = fopen("test.bin","wb");
if (writeFile != NULL)
{
//test int vars
uint8_t test1 = 1;
uint8_t test2 = 2;
uint8_t test3 = 3;
//writing some ints to binary file
fwrite(&test1,sizeof(test1),1, writeFile);
fwrite(&test2,sizeof(test2),1, writeFile);
fwrite(&test3,sizeof(test3),1, writeFile);
fclose(writeFile);
}
else
{
perror("Error opening file to write: ");
return 1;
}
FILE *readFile = fopen("test.bin","rb");
if (readFile != NULL)
{
uint8_t data;
while(fread(&data,sizeof(data),1, readFile)==1){
printf("%d\n", data);
}
fclose(readFile);
}
else
{
perror("Error opening file to read: ");
return 1;
}
return 0;
}
答案 1 :(得分:0)
LP是正确的,如果你有0 <= x <= 255
的范围,你应该考虑uint8_t
。
但是,如果你想使用int
,你可能会得到垃圾的原因是因为
fread(&data,1,1, readFile)==1)
读取单个字节的数据并将其放在指针指定的位置。在您的情况下,这将是data
的最低字节。 Ints通常为4个字节长,因此其他3个字节将保持不变。其他三个字节是什么?好吧,在你的情况下,它们可能是任何东西,因为data
在堆栈上未初始化。